Its urgent solve it fast In an orthogonal cutting test on mild steel, thefollowing data were obtainedCutting speed40 m/minDepth of cutTool rake angle0.3 mm:+ 5°Chip thickness: 1.5 mmCutting force900 NThrust force450 NUsing Merchant's analysis, the friction angle duringthe machining will be

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In an orthogonal cutting test on mild steel, the following data were obtained Cutting speed Depth of cut Tool rake angle : 40 m/min 0.3 mm + 5° Chip thickness 1.5 mm Cutting force 900 N Thrust force 450 N Using Merchant's analysis, the friction angle during the machining will be

In an orthogonal cutting test on mild steel, the following data were obtained Cutting speed Depth of cut Tool rake angle : 40 m/min 0.3 mm + 5° Chip thickness 1.5 mm Cutting force 900 N Thrust force 450 N Using Merchant's analysis, the friction angle during the machining will be

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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We have a rectangular piece. We wish to manufacture a parallel slot along thepiece in a vertical milling machine and 50 cm from the edge. The width of the slot is 40 mm. TheDepth of the slot is 25 mm. For this, several rough cutting steps and aFine cut with a depth of 0.20 mm. The depth for each of the steps ofrough cut is limited to 1.75 mmAditional information:What is the number of blades used for the rough cutting steps?What is the number of blades used for the fine cutting step?
Tuming tests were performed using a coated carbide tool on steel workpiece at feed of 0.30 mm/rev and the depth of cut 4.0 mm. The tests have resulted in 20-min tool life for a cutting speedv 165 m/min and a 60-min tl mie ie a speed v = a) The n and C values in the Taylor tool life equation b) The cubic cm of steel removed in each case 96 m/min. Determine:
2. The following data was obtained from an orthogonal cutting test: Rake angle = 20° Cutting speed = 100 m/min Chip length before cutting = 29.4 mm Chip length after cutting = 12.9 mm Vertical cutting force 1050 N Horizontal cutting force = 630 N Using Merchant's analysis, calculate (a) resultant force (c) friction force and friction angle (b) shear plane angle (d) total work done
Q2:- Tool life tests in turning yield the following data: (1) v = 100 m/min, T = 10 min; (2) v = 75 m/min, T = 30 min. (a) Determine the n and C values in the Taylor tool life equation. Based on your equation, compute (b) the tool life for a speed of 90 m/min, and (c) the speed corresponding to a tool life of 20 min Q3:- In an orthogonal cutting operation, the tool has a rake angle = 15°. The chip thickness before the cut = 0.30 mm and the cut yields a deformed chip thickness = 0.65s mm. Calculate (a) the shear plane angle and (b) the shear strain for the operation. Suppose the rake angle were changed to a= 0°. Assuming that the friction angle remains the same, determine (a) the shear plane angle, (b) the chip thickness, and (c) the shear strain for the operation.
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A mild steel specimen of Initial diameter of 51.5 mm is turned to final diameter of 48 mm for an initial length of 151 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.1 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 7 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 48.8 minutes (a) Find number of passes to finish the entire turning operation (b) The actual length of the turning operation in mm ( (c)The time required to complete one single turning operation in minutes (d) Spindle speed in rpm
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Q4 Tool life of a turning tool is given by VT0.12xfP.7xd3=C at a cutting speed (V) of 25m/min, feed(f) 0.25 mm/rev and job diameter(d) 4 mm, the tool life was 53 minutes. Calculate (i) Tool life if cutting speed increased by 20 % [3]