In the Millikan oil drop experiment tiny charged oil droplets generated by a spray are allowed to fall under gravity through a hole in a top electrode, T, towards a bottom electrode B separated from T by 1 cm. When a holding voltage Vh = +0.25V is applied between T and B the droplets are seen to be suspended motionless between the electrodes. What is the specific charge of the droplet q/m?

In the Millikan oil drop experiment tiny charged oil droplets generated by a spray are allowed to fall under gravity through a hole in a top electrode, T, towards a bottom electrode B separated from T by 1 cm. When a holding voltage Vh = +0.25V is applied between T and B the droplets are seen to be suspended motionless between the electrodes. What is the specific charge of the droplet q/m?

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter29: Introduction To Quantum Physics

Section: Chapter Questions

Problem 62PE: (a) If the position of an electron in a membrane is measured to an accuracy of 1.00 m, what is the...

See similar textbooks

Similar questions

Robert Millikan was an American physicist who in 1909 performed a classic experiment involving charged oil drops. Millikan adjusted the voltage applied between two metal plates in order to suspend charged drops in the resulting electric field. For a suspended drop, the electrostatic force directed up exactly balances out the weight of the drop. Millikan ultimately determined the charge on an electron and that charge is quantized. This means that charge comes in increments, discrete amounts, rather than any amount.A NEGATIVELY-charged oil drop is suspended between two plates of opposite charge by an electric field of 603 newtons per coulomb. The drop is determined to have a mass of 8.86 x 10-17 kilograms. a. What is the charge on the drop? Include units in your answer.
Robert Millikan was an American physicist who in 1909 performed a classic experiment involving charged oil drops. Millikan adjusted the voltage applied between two metal plates in order to suspend charged drops in the resulting electric field. For a suspended drop, the electrostatic force directed up exactly balances out the weight of the drop. Millikan ultimately determined the charge on an electron and that charge is quantized. This means that charge comes in increments, discrete amounts, rather than any amount.A NEGATIVELY-charged oil drop is suspended between two plates of opposite charge by an electric field of 603 newtons per coulomb. The drop is determined to have a mass of 8.86 x 10-17 kilograms.a. What is the charge on the drop? Include units in your answer. More information.b. How many excess electrons does it carry? Hint: Charge is quantized, so this answer must be just an integer.
In the Millikan oil drop experiment tiny charged oil droplets generated by a spray are allowed to fall under gravity through a hole in a top electrode, T, towards a bottom electrode B separated from T by 1 cm. When a holding voltage Vh = +0.25V is applied between T and B the droplets are seen to be suspended motionless between the electrodes. What is the specific charge of the droplet q/m? Select one: a. 0.16 C/kg b. 0.392 C/kg с. 2.7 С/kg O d. 1.5 C/kg
If one of the droplets in the famous oil drop experiment has a charge of - 9.6 * 10 ^ - 19 * C how many excess electrons does the drop contain?
In Millikan's oil-drop experiment, one looks at a small oil drop held motionless between two plates. Take the voltage between the plates to be 2340 V, and the plate separation to be 2.30 cm. The oil drop (of density 0.810 g/cm?) has a diameter of 4.15 x 10- m. Find the charge (in C) on the drop.
If neededBoltzmann Constant=1.38×10-23 J/K = 8.62×10-5eV/KUnit charge= 1.602 ×10-5 CPlanck’s constant= 6.626×10−34 J.sec=4.136×10−15 eV.sec
A velocity selector consists of two parallel plates with an electric field strength of 1600 N/C. Alpha particles with a velocity of vi = 2100 m/s and v2 = 3300 m/s are to be fired horizontally into the middle of the velocity selector (as shown below). The alpha particles travelling at 3300 m/s are to pass through the velocity selector undeflected, while the slower travelling alpha particles will collide with one of the plates. The effects of gravity can be ignored throughout this question. +, Part A Determine the required strength of the magnetic field nνα ΑΣφ ? B = T Submit Request Answer Part B The required direction of the magnetic field will be O down O up O into the page O out of the page Submit Request Answer Part C An alpha particle is a Helium nucleus, which contains two protons and two neutrons, so it has a mass of 6.68x10-27 kg and a charge of 3.20x10-19 C The slower moving alpha particles will accelerate vertically and collide with the top (negative plate). What will be the…
An electron revolves around the nucleus of an atom in a circular orbit of radius 4.0Å with a speed of 6.0 x 10^6 ms-1. Calculate the linear kinetic energy.
A spherical shell of inner radius a cm has a volume charge density p(r, 0) =4/2tr cos 0 c/m³. The potential energy of this configuration is 5 cm and outer radius b = 7 Inner Yadius a=5 cm Outer radius b= 7 cm Volume charge dinsity pcr,@),4 cos0 .clm? Potential Energy
Consider the element Hydrogen. In this atom, assume the electron travels with a speed of 6.8 105 m/s. What is the radius between the nucleus and the orbiting electron in m?
Suppose a capacitor consists of two coaxial thin cylindrical conductors. The inner cylinder of radius ra has a charge of +Q, while the outer cylinder of radius rh has charge -Q. srb The electric field E at a radial distance r from the central axis is given by the function: E = ge/d0 + B/r + bo where alpha (a)., beta (8), ao and bo are constants. Find an expression for its capacitance. First, let us derive the potential difference Voh between the two conductors. The potential difference is related to the electric field by: Edr = - Edr Calculating the antiderivative or indefinite integral, Vab = (-aageao + B + bo By definition, the capacitance Cis related to the charge and potential difference by: C = Evaluating with the upper and lower limits of integration for Vab, then simplifying: C = Q/( (e""b/ao - eTala0) + ß In ) + bo (
An electron moves through a crossed field of 5000 V/m and 5 x 10-4 Wb/m², then its velocity is (a) (c) 106 m/s 108 m/s (b) 107 m/s (d) 10⁹ m/s