In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb=4.4 x 10-4), with 0.50 M HCl, calculate the pH under the following conditions: after 50.0 mL of 0.50 M HCl has been added at the equivalence point
In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb=4.4 x 10-4), with 0.50 M HCl, calculate the pH under the following conditions: after 50.0 mL of 0.50 M HCl has been added at the equivalence point
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 66E: In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb = 4.4 104), with 0.50 M HC1, calculate...
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- In the titration of 50.0 mL of 1.0 M methylamine, CH3NH2 (Kb=4.4 x 10-4), with 0.50 M HCl, calculate the pH under the following conditions:
- after 50.0 mL of 0.50 M HCl has been added
- at the equivalence point
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