Is it possible to write a nonrecursive version of keys() that uses space proportional to the tree height (independent of the number of keys in the range)?
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Is it possible to write a nonrecursive version of keys() that uses space proportional to the tree height (independent of the number of keys in the range)?
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- Below is the IntTree class we discussed in week 3 and that you worked on in HW3. We are in the middle of implementing a new recursive method called leafCount that should return the number of leaves in the tree. What code should replace the comment /* recursive case */ so that the leafCount method works correctly? return tempL + 1; return tempL + tempR + 1; return tempL + tempR; return tempR + 1;public int insert(int value);/* Creates a node with the parameter as its value* and inserts the node into the tree in the appropriate position.* This method should call upon the recursive insert_r() helper method* you write.** we will make the assumption for this assignment (and implement it so) * that the values in a BST are unique... no duplicates** If we insert a value and it succeeded... adds it to the tree* return the element that was added** If we try to add an element and it is a duplicate, return the element* but make no changes to the tree... no new nodes added** @param int value to be inserted in tree* @return integer that was insrted after insertion is done.** Example 1: Suppose we have the tree below:** (27)* / \* (4) (29)* / \* (1) (8)* After calling insert(5), we'd obtain the following tree:** (27)* / \* (4) (29)* / \* (1) (8)* /* (5)** Example 2: Suppose we have the tree below:** (87)* / \* (42) (128)* \ \* (46) (145)* /* (44)** After calling insert(147), we'd obtain the…Using Java, Write a program that will take an array of generic values that are in sorted order in the array, create a binary search tree, and put the values in the array into the tree. Your binary search tree should be complete (“complete” as defined in chapter 24). Or put another way, it should have the fewest number of levels and still be“complete”.Use the following array: “A”, “B”, “C”, “D”, “E”, “F”, “G”, “H”, “I”, “J”, “K”, “L”, “M”,”N”.Remember, your code is to handle generic data types, not just strings. So while I want you to use thespecified array of strings, your program should work if I choose to use an array of Integers, orCharacters. Printout the values from the tree (not the array) in a tree fashion so that I can readily see the treestructure.
- A binary tree is balanced if every node in the tree is such that the heights of its left and right subtrees do not differ by more than one. Complete the pseudo-code method isBalanced which determines if a binary tree is balanced. The function returns a value of -1 if the tree is not balanced, otherwise it returns the height of the tree. Add comments to explain what your code segment is doing. The following definition of a node in the tree is used. class BinaryNode { int element; BinaryNode left; BinaryNode right; } Complete the method below: int isBalanced (BinaryNode t) { int leftCount=0; int rightCount=0; if (t == null) //empty tree, height is 0 return 0; if ((t.left== null) and (t.right== null) return 0; else { . . . . . . . . . } }The for construction is a loops that iteratively processes a given list. Consequently, it works so long even though there are objects to process. What about this claim: true or false?How do you compute the union, intersection, and difference of two sets, using just the methods of the Set interface and without using loops? (Java)
- P1 Suppose we want to create a method for the class BinaryTree (file BinaryTree.java) thatcounts the number of times an object occurs in the tree.a. Write the methodpublic int count1(T anObject)which calls the private recursive methodprivate int count1(BinaryNode<T> rootNode, T anObject)to count the number of occurrences of anObjectb. Write the methodpublic int count2(T anObject)that counts the number of occurrences of anObject and that uses one of the iterators of thebinary tree.Compare the efficiencies of the previous the two methods count1 and count2 using big Onotation. Add your answer as a comment before the function definition P2 Suppose we want to create a method for the class BinaryTree that decides whether two treeshave the same structure. Two trees t1 and t2 have the same structure if:- If one has a left child, then both have left children and the left children are isomorphic,AND - if one has a right child, then both have right children and the right children…Java Code: How to implement logic for ParseDoWhile, ParseDelete, ParseReturn, and ParseFunctionCall where all of the Node data structure correct, parses correctly, throws exceptions with good error messages. Make sure to write block of codes for these four methods.can you please fix the AssertionError in this and also the code: (please don't use try and except or break/continue or recursion) def hike_unique(m: list[list[int]], start_point: tuple[int, int],end_point: tuple[int, int]) -> int: if start_point == end_point:return 0else:front_row = start_point[0]front_column = start_point[1]end_row = end_point[0]end_column = end_point[1]front_eva = m[front_row][front_column]end_eva = m[end_row][end_column]eva_diff = abs(front_eva - end_eva)if front_row == end_row:total_cost = eva_diff * (abs(front_column - end_column)) + 1elif front_column == end_column:total_cost = eva_diff * (abs(front_row - end_row)) + 1else:total_cost = eva_diff * (abs(front_row - end_row) + abs(front_column - end_column)) - 1return total_cost print(hike_unique(sample_map, (1, 1), (0, 0)) It should print 3 if the sample_map is >>> sample_map = [[1, 3], ... [0, 4]] if you do…
- Can someone translate this pseudo code to code in Java? Compute Set• if included sum of root is larger than excluded sum, then set isInSet[root] to true• for each child of root, call computeSetHelper(child, root) Compute Set Helper• if included sum of node is larger than excluded sum and parent is not included in theset, then set isInSet[node] = true• for each child of node, call computeSetHelper(child, node)set, then set isInSet[node] = true• for each child of node, call computeSetHelper(child, node) public void computeSet(int root) { // complete this function } private void computeSetHelper(int node, int parent) { // complete this function }Use the right loop for the right assignment, using all the follow- ing loops: for, while without hasNext(), while with hasNext() and do-while. So I cannot use array. it has to be done in java.Below is the IntTree class. We are in the middle of implementing a new recursive method called leafCount that should return the number of leaves in the tree. What code should replace the comment /* base case 2 */ so that the leafCount method works correctly? Return 0 Return null Return 1 throw new RuntimeException("error");