Ka for ammonium, its conjugate acid. (NH4+) = 5.68 x 10^-10 Using the answer above, what is the pH of a 0.140 M solution of NH4Cl?

Chemistry for Engineering Students
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ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.62PAE: 12.62 Write the formula of the conjugate acid of each of the following bases, (a) OH-, (b) NHj, (c)...
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Ka for ammonium, its conjugate acid. (NH4+) = 5.68 x 10^-10

Using the answer above, what is the pH of a 0.140 M solution of NH4Cl?

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