k=61 N/m 2.8 m The 6.0 kg bar is released from rest at an angle of 0₁ = 25°. The spring attached to the top of the bar was unstretched when the bar was vertical. i) Find the change of the bar's gravitational potential energy as it falls to 0₂ = 35°. Vg.2 - Vg1 = ii) Find the change of the spring's potential energy as it falls to 0₂ = 35°. Vsp.2 - V sp,1 = iii) Write an equation relating the speed of the bar's center to its angular speed at 0₂ = 35°. v(w) = iv) Find the angular speed of the bar when it reaches 0₂ = 35°. W₂ =
k=61 N/m 2.8 m The 6.0 kg bar is released from rest at an angle of 0₁ = 25°. The spring attached to the top of the bar was unstretched when the bar was vertical. i) Find the change of the bar's gravitational potential energy as it falls to 0₂ = 35°. Vg.2 - Vg1 = ii) Find the change of the spring's potential energy as it falls to 0₂ = 35°. Vsp.2 - V sp,1 = iii) Write an equation relating the speed of the bar's center to its angular speed at 0₂ = 35°. v(w) = iv) Find the angular speed of the bar when it reaches 0₂ = 35°. W₂ =
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Transcribed Image Text:k=61 N/m
2.8 m
The 6.0 kg bar is released from rest at an angle
of 0₁ = 25°. The spring attached to the top of the
bar was unstretched when the bar was vertical.
i) Find the change of the bar's gravitational
potential energy as it falls to 0₂ = 35°.
Vg.2 - Vg1 =
ii) Find the change of the spring's potential
energy as it falls to 0₂ = 35°.
Vsp.2 - V sp,1 =
iii) Write an equation relating the speed of the
bar's center to its angular speed at 0₂ = 35°.
v(w) =
iv) Find the angular speed of the bar when it
reaches 0₂ = 35°.
W₂ =
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