kindly help me with this problem thank you ill give like for the answer mixture consists of a certain amount of caffeine dissolved in 100 ml. of water
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kindly help me with this problem thank you ill give like for the answer
mixture consists of a certain amount of caffeine dissolved in 100 ml. of water
a) How much caffeine was originally used when 0.31 g of the organic compound was devolved n watt:, and 150 ml ether was used as extraction solvent
b) How much was dissolved n ether
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- d. All of these. 9. Concentration of the stock solution is 0.30m. Howmuch of it would have to be diluted to the totAl of 10:00ml to get the conc of O. 0005m? a) n ml b) 17 microL c)17 molIf the same mass of Na2SO4 (MW: 142 g/mol) and K2SO4 (MW: 174 g/mol) were weighed and used for the gravimetry experiment, which will yield a greater amount of precipitate? Assume that the experiment was done correctly. Indeterminate, it will depend on the (A amount of BaCl2 used. Na „SO, , because it has a smaller В molecular weight. They will yield the same amount of precipitate because the same mass was initially weighed. K,SO, , because it has a larger (D molecular weight. 4plz do both with detail explanation plz ...do not give incomplete solution
- I NEED HELP PLEASE ASAP!!! Hoping for complete solutions since I’m having a hard time with this. Pls skip if unsure or not willing to answer the subitems (these are all connected for one item). Please show full solution and I'll give thumbs up. Thank you!Benzalkonium Chloride (E=0.16) =1.5g Distilled water qs 0.9% NaCl solution ad =100 mL Make isoton. Sol. Apply on affected area p.r.n. 1. How many mL of distilled water must be added to make the Benzalkonium chloride preparation isotonic? 2. How many mL of 0.9% NaCl must be added to make a 100 mL solution?2 Trial 1: [4] Volume of NaOH, dispensed (mL) Trial 1: [5] Molar concentration of NaOH (mol/L) Trial 2: [4] Volume of NaOH, dispensed (mL) How Trial 2: [5] Molar concentration of NaOH (mol/L) Trial 3: [4] Volume of NaOH, dispensed (mL) Trial 3: [5] Molar concentration of NaOH (mol/L)
- (Preparation of 0.1 N HCI solution in 250 ml D.W) Procedure: Preparation of approximately (0.IN) HCI from 37% and 1.2 Sp.g • Calculate the Normality of the concentrated HCl from the law: To prepare (500ml) of 0.IN HCL: NI VI = N2 V2 NI x ? = 0.1 x 500 • Transfer some of distilled water to 500ml volumetric flask and add the calculated volume of conc. HCI. Mix the content thoroughly. Complete to the mark with distilled water and make a label.T Normal T No Spac... Heading 1 Heading Paragraph Styles 5. Astock solution of 0.1M of NazCO3 is available. How many milliliters are needed to make a 100.0 mL of 0.01M 0.02M 0.03M 0.04M 0.05M solutions?given the molar mass of of compound A as 327.34g/mol and the mass being 0.016g. calculate the concentration of compound A (the stock standard) if it is mixed with 50ml water then 2ml, 4ml and 6ml of the stock standard are measured into a 10ml volumetric flask. calculate the concentrations of the 2ml, 4ml and 6 ml solutions.
- Choose the situation below that would result in a AHsolution near 0 A B O C OD DE O When IAH solvent! >> AHsolutel O When IAHsolutel > AHhydration! O When IAHsolutel1 4 6 7. 8 9. 10 -10 An aqueous solution at 25 °C has a H,O' concentration of 6. x 10 "M. Calculate the OH concentration. Be sure your answer has 1 significant digits. | M Subm Continue © 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy CentCan you help me determine the required amount of 500mg ascorbic acid tablets to puverize the necessary amount of distilled water to make the desired concentration of stock solution (0.1M) Show complete and justifiable computations pls.SEE MORE QUESTIONS
