Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 103 inches) of the aluminum bar. 0.02 in. 14 in. Bronze A = 2.4 in² E = 15 × 106 psi a = 12 x 10-6/°F 18 in. Aluminum A = 2.8 in² E = 10.6 × 106 psi a = 12.9 x 10-6/°F

Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 103 inches) of the aluminum bar. 0.02 in. 14 in. Bronze A = 2.4 in² E = 15 × 106 psi a = 12 x 10-6/°F 18 in. Aluminum A = 2.8 in² E = 10.6 × 106 psi a = 12.9 x 10-6/°F

Materials Science And Engineering Properties

1st Edition

ISBN:9781111988609

Author:Charles Gilmore

Publisher:Charles Gilmore

Chapter6: Introduction To Mechanical Properties

Section: Chapter Questions

Problem 6.2P

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2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to 11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. 14 in. 18 in. ਕਰ Bronze A = 2.4 in² E-15 x 105 psi a = 12 x 10-6/"F Aluminum A = 2.8 in² E = 10.6 x 105 psi a = 12.9 × 10-5/"F
Knowing that a 0.02in gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11ksi, (b) the corresponding exact length (2 decimal places in 10-3 inches) of the aluminum bar. 0.02 in. 14 in. 18 in. Bronze Aluminum A = 2.4 in? E = 15 × 10° psi a = 12 × 10-6/°F A = 2.8 in² E = 10.6 × 10° psi a = 12.9 × 10-6/ºF
Question 2) Knowing that a 0.02-in. gap exists when the temperature is 75 °F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. -14 in. Bronze A = 2.4 in² E = 15 x 10 psi a = 12 x 10-6/°F -18 in.- Aluminum A = 2.8 in² E = 10.6 x 105 psi a = 12.9 x 10-6/°F
In the figure shown below, determine: 1) The final temperature if the normal stress at aluminium is Og = -90 MPa and the initial temperature %3D 20°C. 2) The final length of the aluminium member. Aluminum A=1800mm? Bronze A=1500mm? E=73GPA E=105GPA a=23.2x10-6/°C a=21.6x10-6/°C Gap=0.5mm 0.35m 0.45m
In the figure shown below, determine: 1) The final temperature if the normal stress at aluminium is Oal = -90 MPa and the initial temperature 20°C. 2) The final length of the aluminium member. Aluminum A=1800mm2 Bronze A=1500mm? E=105GPA a=21.6x10-6/°C E=73GPA a=23.2x10-6/°C Gap=0.5mm 0.35m 0.45m
2.58 Knowing that a 0.02-in. gap exists when the temperature is 75°F, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -11 ksi, (b) the corresponding exact length of the aluminum bar. 0.02 in. -14 in. 18 in. Aluminum A = 2.8 in² Bronze A = 2.4 in² E = 15 × 10º psi a = 12 x 10-6/°F E = 10.6 × 106 psi α = 12.9 x 10-6/°F Fig. P2.58 and P2.59
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