Let f(x) = x − 1 + 1/4 cosx = 0 a. Show that f(x) admits only one root ? ∈ [0,1]. b. In order, to approximate r, make 1 iteration using Newton’s method choosing x0 = 0. c. Consider the following method of fixed point xn+1 = g(xn) with g(xn) = 1 −1/4 cos(xn) i. Show that this method converges to r. ii. Determine an approximated value of r such that the error is less than 10^−1 .(choose x0 = 0.2) Newton Raphson formula: xn+1 = xn - f(x)/f'(x)
Let f(x) = x − 1 + 1/4 cosx = 0 a. Show that f(x) admits only one root ? ∈ [0,1]. b. In order, to approximate r, make 1 iteration using Newton’s method choosing x0 = 0. c. Consider the following method of fixed point xn+1 = g(xn) with g(xn) = 1 −1/4 cos(xn) i. Show that this method converges to r. ii. Determine an approximated value of r such that the error is less than 10^−1 .(choose x0 = 0.2) Newton Raphson formula: xn+1 = xn - f(x)/f'(x)
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Let f(x) = x − 1 + 1/4 cosx = 0
a. Show that f(x) admits only one root ? ∈ [0,1].
b. In order, to approximate r, make 1 iteration using Newton’s method choosing x0 = 0.
c. Consider the following method of fixed point xn+1 = g(xn) with g(xn) = 1 −1/4 cos(xn)
i. Show that this method converges to r.
ii. Determine an approximated value of r such that the error is less than 10^−1 .(choose x0 = 0.2)
Newton Raphson formula: xn+1 = xn - f(x)/f'(x)
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