Let's assume that there is an epiallele in mice that causes their fur to become purple. The epiallele is P' for purple fur and the normal allele B for black fur. If we have a heterozygote individual what would happen with its alleles? The epiallele would transform the regular allele into an epiallele through epigenetic mechanisms O The epialiele would silence the expression of the regular allele The epiallele would only affect the offspring of that individual The epiallele would transform the regular allele into an epiallele through genetic mechanisms The epiallele would be silenced by the regular allele
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- Suppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture)(ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Suggest one other aspect of mouse morphology or physiology that you might expect to be altered in the absence of Protein B. Briefly explain your reasoning. Also, based on the apparent effect of Protein B on the likelihood of PCD/Apoptosis, would you classify Protein B as the product of a proto-oncogene or of a tumor suppressor gene?Suppose that you are studying the role of Protein B, which you believe plays a role in regulating PCD/Apoptosis in mice. You create two lines of mutant mice. One (bb) is homozygous for a loss-of-function allele of gene B. The other (Bb) is heterozygous, with one wild-type allele and one loss-of function allele. Initially you pay particular attention to two phenotypes of the resulting mice:(i) The morphology of their paws (see picture) (ii) The size of their brains & shape of their skulls. The bb mice have unusually large brains and unusual protrusions from their skulls. Based on these data, does it appear that Protein B, when present and active, favors or inhibits PCD/Apoptosis?Briefly explain your reasoning. The answer should address both the paw and brain/skull data.stion 20 of 20 CO Epigenetics is the study of heritable traits that are not induced by changes to DNA sequence. Epigenetic changes can be inherited during somatic cell division to regulate the daughter cells of an individual organism. Most epigenetic modifications are reset prior to meiosis. However, some epigenetic changes can be inherited across generations. For example, environmental factors such as nutrition and chemical exposure can induce heritable epigenetic changes in animal models (Relton and Davey Smith, 2012). Genome imprinting is one type of epigenetic modification in which a cell or organism can reduce the expression of a gene and thereby silence the gene. Genome imprinting is caused by DNA methylation and histone modification, which reduce expression of a gene. The silencing occurs in a parent-of-origin-specific manner, where either the maternally derived allele or the paternally derived allele is imprinted and silenced. Expression occurs only through the nonimprinted…
- Lamarck is remembered for his theory of inheritance which hypothesized that physical characteristics acquired during an individuals lifetime were passed onto their offspring (long neck in giraffes). How does this differ from epigenetic inheritance where the diet of the agouti/diabetic mother affects coat color and body size of the offspring (born brown and slim)? O The change in coat color occurs in the offspring and not in the mother O Diet has no impact on fur color, but it can effect body size O There is no difference between Lamarckian theories of inhertiance and epigenetic inheritance O Many genes are involved in determining fur color and body size, making it unlikely that DNA methylation can cause a persistent change in fur color and body sizeThe following genotypes of two independently assorting autosomal genes determine coat color in rats:A-B- (gray); A-bb (yellow); aaB-(black); aabb (cream)A third gene pair on a separate autosome determines whetherany color will be produced. The CC and Cc genotypes allow coloraccording to the expression of the A and B alleles. However,the cc genotype results in albino rats regardless of the A and Balleles present. Determine the F1 phenotypic ratio of the followingcrosses: (a)AAbbCC * aaBBcc; (b) AaBBcc * AABbcc;(c) AaBbCc * AaBbcc.The Drosophila gene Sex lethal (Sxl) is deserving of itsname. Certain alleles have no effect on XY animals butcause XX animals to die early in development. Other alleles have no effect on XX animals but cause XY animals to die early in development. Thus, some Sxl allelesare lethal to females, while others are lethal to males.a. Would you expect a null mutation in Sxl to causelethality in males or in females? b. Why do Sxl alleles of either type cause lethality ina specific sex?The gene transformer (tra) gets its name from sexualtransformation, as some tra alleles can change XXanimals into morphological males, while other traalleles can change XY animals into morphologicalfemales.c. Which of these sex transformations would becaused by null alleles of tra and which would becaused by constitutively active alleles of tra?d. In contrast with Sxl, null tra mutations do notcause lethality either in XX or in XY animals.However, the Sxl protein regulates the productionof the Tra protein. Why…
- Let’s suppose that a species of mosquito has two different types ofsimple transposons that we will call X elements and Z elements.The X elements appear quite stable. In a population of 100 mosquitoes,it is found that every mosquito has 6 X elements, and theyare always located in the same chromosomal locations amongdifferent individuals. In contrast, the Z elements seem to movearound quite a bit. Within the same 100 mosquitoes, the number of Z elements ranges from 2 to 14, and the locations of the Z elementstend to vary considerably among different individuals. Explainhow one simple transposon can be stable and another simple transposoncan be mobile, within the same group of individuals.In wheat, aleurone cells form a thin layer of the seed coat that is critical to early gene expression in plant development. The color of this layer of cells is controlled by two alleles of a gene [colored aleurone (R) is dominant to colorless (r)]. A second gene is known to control the color of leaf tips [green leaf tip (G) is dominant to yellow (g)]. Two plants, each heterozygous for both characteristics, are test crossed to homozygous recessives, and their progeny are combined to produce the following totals: colored green 102 colored yellow 98 colorless green 103 colorless yellow 97 a) Use chi-square analysis to test these data for an independent assortment of the two characteristics (table provided). Please show work, how your expected values are calculated, and explain what your results indicate about the data. b) You decide to be cautious in your analysis, and decide to analyze the progeny from each of the crosses individually (instead of adding them together as shown above).…An epigenetic study of maternal care in mice was used to study transgenerational epigenetic inheritance. This study found that increased maternal care during childhood resulted in lower stress levels as adults and decreased maternal care with their own offspring. Increased maternal care during childhood resulted in lower stress levels as adults and increased maternal care with their own offspring. Increased maternal care during childhood resulted in higher stress levels as adults and decreased maternal care with their own offspring. Increased maternal care during childhood resulted in higher stress levels as adults and increased maternal care with their own offspring.
- In Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c 460a + + 450a b c 32+ + + 38a + c 11+ b + 9 No other phenotypes were observed.(a) Determine the correct sequence and construct amap of these genes on the X chromosome ?In Drosophila, a heterozygous female for the X-linkedrecessive traits a, b, and c was crossed to a male that phenotypically expressed a, b, and c. The offspring occurred inthe following phenotypic ratios.+ b c 460a + + 450a b c 32+ + + 38a + c 11+ b + 9 No other phenotypes were observed.(a) What is the genotypic arrangement of the alleles ofthese genes on the X chromosome of the female?Use the dropdowns to indicate the pattern of methylation and gene expression expected for a maternally-imprinted gene in the somatic cell of a male individual. The Somatic cell would show [Select] male's male parent, and [Select] male's female parent. As a result, [Select] of the allele inherited from the of the allele inherited from the could be expressed. The pattern of methylation would be [Select] imprinted gene in a somatic cell of a female individual. for the same maternally-