make Algorithm to Auxiliary methods for the lockstep protocol. in: set of senders S out: set of messages M
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- The function f(R, K) = P(S(E(R XOR K)) of the DES cryptographic protocol manipulates different sizes of bit-strings. The bit-string sizes of P-SEK in this order are: 32-48-48-32 32-32-48 48 48-48-32-32 64-32-32 48 64 48 32-64 SAVEWrite Algorithm for Auxiliary methods for the lockstep protocol.In an RPC-like protocol, where numerous requests can be active at the same time and responses can be given in any sequence, the following is possible: Pretend requests are sequentially numbered, and that ACK[N] confirms the receipt of reply[N]. Should the number of ACKs be cumulative? If not, what should happen in the event that an ACK is not received?
- make Algorithm to Auxiliary methods for the lockstep protocol.in: set of senders Sout: set of messages MIn an RPC-like protocol, where numerous requests can be active at the same time and responses can be given in any sequence, the following is possible: Pretend requests are sequentially numbered, and that ACKIN] confirms the receipt of reply[N]. Should the number of ACKS be cumulative? If not, what should happen in the event that an ACK is not received?|Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (d) What will be the window size of PC A after receiving only the first segment from webserver? (e)…
- For the Zhou-Gollman non-repudiation protocol discussed in the lecture on “Non-Repudiationand Anonymity Protocols”, which one of the following statements is false:Please solve it correctly and please provide explanation of your answers. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. (a) What will be the sequence number of the third TCP handshake signal send from PC to webserver?…When Bob wants to send Alice a message M on the Internet, he breaks M into n data packets, numbers the packets consecutively, and injects them into the network. When the packets arrive at Alice’s computer, they may be out of order, so Alice must assemble the sequence of n packets in order before she can be sure she has the entire message. Describe an efficient scheme for Alice to do this. What is the running time of this algorithm? From Data Structures and Algorithms C-7.56
- In the generic SR protocol, the sender transmits a message as soon as it is available (if it is in the window) without waiting for an acknowledgment. Suppose now that we want an SR protocol that sends messages two at a time. That is, the sender will send a pair of messages and will send the next pair of messages only when it knows that both messages in the first pair have been received correctly.Supposethat the channel may lose messages but will not corrupt or reorder messages. i) Outline an error-control protocol for the unidirectional rdt of messages. ii) Give an FSM description of the sender and receiver. iii) Describe the format of the packets sent between sender and receiver and vice versa. iv) If you use any procedure calls other than those in SR protocol (for example, udt_send(), start_timer(), rdt_rcv(), and so on),clearly state their actions. v) Give an example (a timeline trace of sender and receiver) showing how your protocol recovers from a lost packetIn an RPC-like protocol, many requests can be active at the same time, and responses can be sent in any order: Assume that requests are sequentially numbered and that ACK[N] acknowledges reply[N]. Should ACKs be added up? If not, what should happen if an ACK is not received?Please solve it correctly and please provide explanation of your answers. Please answer parts g, h and i. A PC and a Web Server are communicating over a TCP connection. The PC had started the three way handshake with the initial sequence number of 3069 . The Web Server's initial sequence number is 4830 . The window size of the PC is 815 bytes and the window size of the Web Server is 463 bytes. Using the third TCP handshake ack segment the PC sends the http request of the size 396 bytes to the Web Server. Then the Web Server answers with 3 segments containing the requested data. The first segment size is 42 bytes and the second segment size is 276 bytes and the third segment size is 146 bytes respectively. The PC receives all three segments within the timer. But unfortunately the second segment was corrupted. So the PC immediately sends an acknowledgement segment. Assume that the PC uses Selective Repeat/Reject ARQ. g) The second segment from webserver was corrupted. So the PC…