(Manning equation) (a) Determine the maximum flowrate possible for the creek shown in the figure below if it is not to overflow onto the floodplain. The creek bed drops an average of 5.11 ft/half-mile of length. (b) Determine the flowrate during a flood if the depth is 8 ft. Light brush floodplain Clear, straight 8 ft 4 ft (a) i 50 ft 7 ft channel 6 ft Pasture floodplain -5 ft 80 ft ft³/s (b) i ft³/s 8 ft
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- What is the discharge capacity of an irrigation channel having a total depth of 1.5 meter (including freeboard) , bottom width 1.2 m, side slope 2:1, and a hydraulic gradient of 0.001 m/m? Assume n=0.04 and freeboard to be 20% of the flow depth.In a 3.0 m wide open rectangular channel, the flow rate is (1158) lt/sec flows. The depth of the channel is 2.9 m. At a downstream section, there is constriction with a width of 2.50 m and a 0.20 m bump on the bottom. Calculate the water depths of both upstream and downstream.what is the depth of uniform flow rate in a rectangular planned woood channel with Manning's n=0.012,width of 2.0m and a bed slope of 0.002,when the flow rate is 4m3/s
- An urban drainage consists of an underground pipe of diameter d=0.9m laid on a slope of 0.002 and discharges the flood discharge at a depth of 0.8d. If the Manning’s roughness coefficient of the pipe is n= 0.015, what is the magnitude of the flood discharge. Determine also: i) the normal depth flow ii) ) the critical depth corresponding to this flow iii) the Froude number of flow and iv) the type of flowA trapeziodal channel lined with grass (n = 0.027) has a bottom width of 4.25 feet, side slopes of 2 horizontal to 1 vertical, and a slope of 1.1 percent. Water is flowing at a depth of 2.35 feet. a) what is the discharge? b) what is the velocity?A rectangular channel section increases in width from 40 ft to 50 ft in a length of 100 ft. The channel slope is 0.1%. If the discharge and the velocity of flow at section 1 are 2950 cfs and 12.8 ft/sec, respectively, determine the depths of flow at sections 1 and 2 and the velocity at section 2. Use the energy principle. Disregard the losses.please show step by step.
- Water flows over a 1.5-m-high sharp-crested rectangular weir. The flow depth upstream of the weir is 2.5 m, and water is discharged from the weir into an unfinishedconcrete channel of equal width where uniform-flow conditions are established. If no hydraulic jump is to occur in the downstream flow, determine the maximum slope of the downstream channel.A right-angled triangular channel carries a flow of 16,000 l/s. The Manning’s n = 0.020 and the slope is 2 m/3000 m.(a) Determine the critical depth [m] for this flow.(b) Determine Froude number for the flow when the depth of flow is 0.6 m.(c) Determine the normal depth of flow [m]5.0-m wide rectangular channel carries a discharge of 6.40 m³/s at a depth of 0.8 m. At section there is a smooth drop of 0.22 m in the bed. What is the water surface elevation downstream of the drop?
- ) Determine the critical flow depth in a long length of lined trapezoidal channel of base width of 3.5 m and a side slopes of 1:1 when the flow rate is 20 m3/s. the normal depth is 1.727m.4. A trapezoidal channel with 3 meters bottom width, side slope 2H:1V, channel gradient of 0.002, and n= 0.025, carries a discharge of 200m^3/min. Compute the normal depth and velocity.Qle: A flow rate of 2.4m ^ 3 /sec is to be carried in an open channel at a velocity of 1.5 m/sec. If the channel cross section is trapezoidal with water depth equal to the width of the channel bottom and side slope of 1:1. Manning roughness coefficient is 0.03. Determine: a) The bottom width b) The channel bed slope