may need to use the appropriate technology to answer this question. market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The chase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or al to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use a = 0.05 and the following data to test the othesis and comment on the value of the commercial. Individual 1 2 3 4 5 6 7 8 Purchase Rating After 6 6 7 4 3 9 7 6 Before 4 8 3 5 8 5 7

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A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use 
? = 0.05
 and the following data to test the hypothesis and comment on the value of the commercial.
Individual Purchase Rating
After Before
1 6 5
2 6 4
3 7 8
4 4 3
5 3 5
6 9 8
7 7 5
8 6 7
 
a. State the null and alternative hypotheses. (Use ?d = mean rating after − mean rating before.)
b. Calculate the value of the test statistic. (Round your answer to three decimal places.)
c. Calculate the p-value. (Round your answer to four decimal places.)
You may need to use the appropriate technology to answer this question.
A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The
purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or
equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use α = 0.05 and the following data to test the
hypothesis and comment on the value of the commercial.
Individual
1
2
3
4
5
6
7
8
Purchase Rating
After
6
6
7
4
3
9
7
6
Before
5
4
8
3
5
8
5
7
Transcribed Image Text:You may need to use the appropriate technology to answer this question. A market research firm used a sample of individuals to rate the purchase potential of a particular product before and after the individuals saw a new television commercial about the product. The purchase potential ratings were based on a 0 to 10 scale, with higher values indicating a higher purchase potential. The null hypothesis stated that the mean rating "after" would be less than or equal to the mean rating "before." Rejection of this hypothesis would show that the commercial improved the mean purchase potential rating. Use α = 0.05 and the following data to test the hypothesis and comment on the value of the commercial. Individual 1 2 3 4 5 6 7 8 Purchase Rating After 6 6 7 4 3 9 7 6 Before 5 4 8 3 5 8 5 7
State the null and alternative hypotheses. (Use μd = mean rating after mean rating before.)
= 0
Ho: Md=
Ha: Md #0
Ho: Md > O
Ha: Md ≤ 0
Ho: Md # 0
Ha: Md
Ho: Md ≤0
Ha Md
= 0
Ho: Md
≤0
Ha: Md > 0
X
Calculate the value of the test statistic. (Round your answer to three decimal places.)
0.704
Calculate the p-value. (Round your answer to four decimal places.)
p-value = 0.5042
X
Transcribed Image Text:State the null and alternative hypotheses. (Use μd = mean rating after mean rating before.) = 0 Ho: Md= Ha: Md #0 Ho: Md > O Ha: Md ≤ 0 Ho: Md # 0 Ha: Md Ho: Md ≤0 Ha Md = 0 Ho: Md ≤0 Ha: Md > 0 X Calculate the value of the test statistic. (Round your answer to three decimal places.) 0.704 Calculate the p-value. (Round your answer to four decimal places.) p-value = 0.5042 X
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