mov r0, # 6Ah mov psw, # 00h mov a, # 22h ric a M90100564-871890336 598836 b19010056498715868 715983 The final value of the accumulator is 44h. A 100 1598836 871598836 100 100504-0/1688

Q: C++ only Example Input: 2 15 100 123456789 9876543 Output: 70 102768568246676

A: As asked I have answered the question in C++

Q: C++ only Example Input: 2 15 100 123456789 9876543 Output: 70 102768568246676

A: C++ Code is written below with the

Q: v2 e2 V3 e5 e4 ez e7 V7 eg e11 V4 v6 eg V5 е 10 True O False

A: Solution

Q: Urgent C++ Code  Example Input: 2 15 100 123456789 9876543 Output: 70 102768568246676

A: I have solved the question in C++

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A: It is defined as a low-level programming language for a computer or other programmable device…

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A: A) 2.046 rad/sec

Q: 0 Change log8 126 to log2 Change log2 816 to log8 Change log 0.46 to loge

A: Q. Simply: Change loge 126 to log10 Change log8 126 to log2 Change log2 816 to log8 Change log 0.46…

Q: C++ Code  Example Input: 2 15 100 123456789 9876543 Output: 70 102768568246676

A: I have answered the question is C++;

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A: I have given answer in step2

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A: The question is to decipher the huffman code.

Q: Example Input: 2 15 100 123456789 9876543 Output: 70 102768568246676

A: I have provided the c++ code below along with the output.

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Q: only Example Input: 2 15 100 123456789 9876543 Output: 70 102768568246676

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A: I have given solution in step2

Q: The unsigned integer is О а. -128 t0 +127 O b. 0 to 65535 о с. 0to 255 O d. -32.768 to +32.767

A: Please find the answer below :

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A: Y=(-B+SQRT(B*B-4*A*C))/(2*A)

Q: BCD5421 code for number 10(423) 0100 0010 0011 0010 0100 1100 1000 0010 0011 0010 0100 0011 O O

A: your question is about BCD5421 code let's see the solution of the question

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A:

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A:

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A: It is defined as a interpreted, object-oriented, high-level programming language with dynamic…

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A: The correct answer is given below:-

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Q: R-> XRX | S S-> аTb | bTa T-> XTX | X | 2 X->a | b

A:

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A: all these three numbers are already in standard form. i write both standard and normal number   a)…

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A: the solution is an given below :

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A: I have provided a solution in step2.

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A:

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A:

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Q: Answer in c programming language Code.txt YYC YEG YQX YQM YHZ YHM YXU YUL YOW YQB YQR YXE YYT YYZ…

A: The, code has given below: