The reaction is 2 SmCl3(aq) + 6 Li(aq) → 2 Sm(s) + 6 LiCl(aq) Calculate the free energy change and the cell potential for the reaction at 298.0 K if all reactants are at 2.00 M and/or 2.00 atm and all products are at 0.0100 M and/or 0.0100 atm. Make sure to write half reactions while calculating.
The reaction is 2 SmCl3(aq) + 6 Li(aq) → 2 Sm(s) + 6 LiCl(aq) Calculate the free energy change and the cell potential for the reaction at 298.0 K if all reactants are at 2.00 M and/or 2.00 atm and all products are at 0.0100 M and/or 0.0100 atm. Make sure to write half reactions while calculating.
Chapter19: Applications Of Standard Electrode Potentials
Section: Chapter Questions
Problem 19.8QAP
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The reaction is
2 SmCl3(aq) + 6 Li(aq) → 2 Sm(s) + 6 LiCl(aq)
Calculate the free energy change and the cell potential for the reaction at 298.0 K if all reactants are at 2.00 M and/or 2.00 atm and all products are at 0.0100 M and/or 0.0100 atm. Make sure to write half reactions while calculating.
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my question was why is E° = 0, you never answered this .
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whys is E° = 0 , isn't it E°cell = E°red,cathode - E°red,anode E°cell = -(-2.37 V) - (-3.05 V) = 0.68 V
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