Please I want answer of that question from these choices Select the 5 correct answers from the list below/:Select one or more:O a. 0.0940110990326852O b. 19.6C.277418.437450017O d. 8.4e. 6.28919957889776O f.11.2g. 36.6226559899448h. 4.4922854134984O i.3.59382833079872O j. 55483.6874900034O k. 26.1590399928177I.166451.06247001m. 0.117513873790856n.16.8O o. 0.0470055495163426p. 41.8544639885084O q. 14Or.0.0705083242745139O s.110967.374980007O t.2.69537124809904O u.5.39074249619808V.31.3908479913813w. 0.0235027747581713Х.47.0862719870719O y. 221934.749960014 The bolted coupling in Figure 5 is subject to a torque equal to 354Nm.The solid shaft has a diameter of 41mm. The PCD of the coupling bolts is 63mm.The bolt diamter is 3mm, and the yield strength of the bolt and shaft is 203.54MPA. Using clockwise positive polar co-ordinates:Figure 5.- BoltD'Determine the Polar Moment of Area of the shaft (Answer in mm^4 only).Determine the von Mises Shear Strength (Answer in GPa only).Determine the Shear Stress on the central shaft (MPa).Determine the Factor of Safety for the central shaft.Determine the minimum number of bolts required to transmit the torque without failing (roundup).

Given data-T=354Nm D=41mmPCD=63mm

naft has a diameter of 41mm. The PCD of the coupling bolts is 63mm. amter is 3mm, and the yield strength of the bolt and shaft is 203.54MPA. Using clockwise positive polar co-or Figure 5. Bolt D' Determine the Polar Moment of Area of the shaft (Answer in mm^4 only). Determine the von Mises Shear Strength (Answer in GPa only). Determine the Shear Stress on the central shaft (MPa). Determine the Factor of Safety for the central shaft. Determine the minimum number of bolts reguired to transmit the torque without failing (roundup).

naft has a diameter of 41mm. The PCD of the coupling bolts is 63mm. amter is 3mm, and the yield strength of the bolt and shaft is 203.54MPA. Using clockwise positive polar co-or Figure 5. Bolt D' Determine the Polar Moment of Area of the shaft (Answer in mm^4 only). Determine the von Mises Shear Strength (Answer in GPa only). Determine the Shear Stress on the central shaft (MPa). Determine the Factor of Safety for the central shaft. Determine the minimum number of bolts reguired to transmit the torque without failing (roundup).

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.2.4P: Repeat Problem 11.2-3 assuming that R= 10 kN · m/rad and L = 2 m.

See similar textbooks

Similar questions

03: A shaft carrying three loaded pulleys with stepped diameters as shown. The modulus of rigidity for the shaft is (G-28GPA) and the shaft segments have the same lengths 48N.m (AB-BC-CD-30Cm). Determinc the following: GON.m 144N,m 1- Maximum shearing stress in the shaft CD. 2- The angle of twist of the pulley A relative to B.
A solid constant-diameter circular shaft is subjected to the torques of TA = 480 lb-ft, TB = 1060 lb-ft, Tc= 860 lb-ft, and Tp = 280 lb-ft, acting in the directions shown. The bearings shown allow the shaft to turn freely. (a) Plot a torque diagram showing the internal torque in segments (1), (2), and (3) of the shaft. Use the sign convention presented in %D Section 6.6. (b) If the allowable shear stress in the shaft is 5800 psi, what is the minimum acceptable diameter for the shaft? TB TA Tc (1) Tp (3) В C D Answer: (a) T1 = Ib-ft T2 = Ib-ft T3 = Ib-ft (b) d = in.
A static shaft is subjected to torques at A, B, and C. It has a diameter of 58 mm and is made from 2014-T6 aluminum. If the maximum allowable magnitude of the angle of twist of C relative to A is 0.04 rad, what is the maximum value for the torque T? A aT T cc i❀O 2021 Cathy Zupke parameter value 1.4 1.6 0.6 L₁ L2 α B units m m [-] (1-a )T The maximum value for T is 1.56 X kN.m.
In the design in the figure, a force of Fn=45992 N acts in the vertical plane on a machine element with a diameter of D=200 mm on the shaft resting on the A and B bearings. If the angle made by this force with the horizontal is b=40o, find the life of the 6210 coded Deep Ball bearing to be used in the B bearing, in hours. Number of revolutions = 30 rpm. 1-) The diameter of the machine element on which the force acts will be taken into account in the calculation of bearing forces (That is, it will be assumed that the Fn force AFFECTS THE GROUND shown in the figure, NOT the axis of the shaft). 2-) Pi number will be taken as 3.14.
A B D Do F 240 N.mm 420 N.mm 300 N.mm 480 N.mm Figure 1 - Torques applied to the driveshaft 1) DERIVE the twist angle expression (mathematical) of the shaft under torque in terms of the geometric properties of the shaft and the applied torque 2) CALCULATE the diameter of the shaft if the twist angle should not exceed 1.5⁰ 3) CALCULATE the maximum shear stress due to torsion. Consider G = 70 GPa. Assume that the length between each segment is 500 mm.
Shafts ab and ce are support by pillow bearing blocks as shown. Compute the angle of twist at point a. Report your answer in degrees to two decimal places. 35 in A Y bearing bearing gear c: radius 2.0 in 2 in-k gear b: shaft ab: shaft ce: radius 5.0 in b a radius 0.5 in 5 in-k radius = 0.7 in d. bearing e bearing all shafts: G = 12000 ksi 25 in 30 in
Design a rigid flange coupling to transmit a torque of 228N-m between two coaxial shafts. The shaft is made of alloy steel, flanges out of cast iron and bolts out of steel. Four bolts are used to couple the flanges. The shafts are keyed to the flange hub. The permissible stresses are given below: Shear stress on shaft =100MPa Bearing or crushing stress on shaft =250MPa Shear stress on keys =100MPa Bearing stress on keys = 250MPa Shearing stress on cast iron = 200Mpa Shear stress on bolts =100MPa > Provide FBD
Design a rigid flange coupling to transmit a torque of 250N-m between two coaxial shafts. The shaft is made of alloy steel, flanges out of cast iron and bolts out of steel. Four bolts are used to couple the flanges. The shafts are keyed to the flange hub. The permissible stresses are given below: Shear stress on shaft =100MPa Bearing or crushing stress on shaft =250MPa Shear stress on keys =100MPa Bearing stress on keys = 250MPa Shearing stress on cast iron = 200Mpa Shear stress on bolts =100MPa Torque = 257N-m
Design a rigid flange coupling to transmit a torque of 257N-m between two coaxial shafts. The shaft is made of alloy steel, flanges out of cast iron and bolts out of steel. Four bolts are used to couple the flanges. The shafts are keyed to the flange hub. The permissible stresses are given below: Shear stress on shaft =100MPa Bearing or crushing stress on shaft =250MPa Shear stress on keys =100MPa Bearing stress on keys = 250MPa Shearing stress on cast iron = 200Mpa Shear stress on bolts =100MPa Answer in Word please
What is the minimum diameter of a solid steel shaft that will not twist through more than 4o in a 9 m length when subjected to a torque of 11 kN.m ? if G = 83 GPa
A shaft is designed to transmit power of 100 kW at 180 rpm. The allowable shear stress is 50MPa and modulus of rigidity of 80 GPa. The angle of twist is not to exceed to 1° in 4-meter length A. Calculate the diameter of the shaft in inches. B.If the shaft in A is to be fitted to a hub with material SAE 0105 and fit classification of FN3, what will be the maximum and minimum stresses based on the interference of metal.
For the free body diagram of the shaft shown below, the rolling contact bearings are located at A and C. For the bearing at A, the desired design load for the bearing is Tangential Direction for Gear Y-X axes: Radial Direction for Gear Z-X axes: 1000 Ibf 500 Ibf A A В 500 Ibf 500 Ibf 250 Ibf 250 Ibf