tensile testPCKN)AL (Mm)Dimensions of the samplebe fore e xamin ation4.120. 29D= 9.5mmL=507.640.55120.9115, 8 4l.2719.51.62५.32.11283.5Dimensions of the sampleafter exam ination31.25.25d - 5.733.62=?358.7535.71o.53612.231.515.727.815.8

ΔL (kN) P (N) Strain Stress (MPa) 0 0 0.000 0.0 0.29 4.12 0.006 58.2 0.55 7.64 0.011 107.8…

Answered: nensions Fore e Xamin

Engineering

Mechanical Engineering

nensions Fore e Xamin

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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3. A strip of chicken skin was excised for mechanical testing in tension. The initial dimension of the rectangular specimen was 30 mm long and 15 mm wide, with average thickness of 3 mm. The mechanical testing was conducted at a rate of 5 mm/sec. The following data were obtained: gauge length, mm 20 22 24.2 26.3 27.9 30.1 force, N 0 0.8 2.7 7.9 12.9 19.6 a. Calculate the engineering stresses and strain from the information given and plot the stress-strain curve. Assume that 5 mm of the specimen length is clamped by the testing grip at each end, such that the initial gauge length of the specimen is 20 mm.
The following data were recorded during the tensile test of a 12.8 mm diameter stainless steel rod. The gauge length was 50.8 mm. Load Length Load Length mm mm 107.800 51.308 119,400 51.562 128,300 51.816 149,700| 52.832 50.800 50.825 12,700 25.400 50.851 38,100 50.876 50,800 76,200 89,100 92,700 102,500 51.181 124,700 56.642 50.902 50.952 159,000 53.848 160,400| 54.356 159,500 54.864 51.054 151,500 55.880 51.003 using the data above plot the stress-strain diagram and determine the following mechanical properties Q1 The proportional limit Q 2 The modulus of elasticity Q 3 yield point Q5 The Últimate Tensile Strength Q 4 yield strength at 0.2% offset Q 6 rupture strength
Home work for tensile test The following data was obtained from a tensile test on 135 Load (kN) Extension (mm) 16 32 56 72 95 110 132 142 140 0.2 0.4 0.7 0.9 1.5 2.5 5.0 8.5 10.0 12.0 a specimen of 10mm diameter and gauge length 60mm. Using the graph paper supplied, plot the load-extension diagram and determine: (1) The tensile strength (2) 0.1% Proof Stress (3) Young's Modulus for the specimen
23 Q5. Whate is thc exact reading for the following in mm -10 1. Reading= TTTTE 4.30 012343 -20 10 2.75 2. Reading= TTE 012 20 20 -15 3. Reading=. -10 MITT 5 0123E 3.85 USF
The following data were recorded during the tensile test of a 12.8 mm diameter stainless steel rod. The gauge length was 50.8 mm. Load Length Load Length N N 50.800 107.800 51.308 50.825 119,400 51.562 128,300| 51.816 149,700 52.832 50.902 159,000 53.848 160,400 54.356 159,500 54.864 151,500 55.880 124,700 56.642 mm mm 12,700 25,400 38,100 50,800 76,200 89,100 92,700 102,500 | 51.181 50.851 50.876 50.952 51.003 51.054
Desuon T EHide blocks Determine the Young's modulus of a metal alloy having the following tensile stress-strain diagram. ot yet nswered Stress-Strain Diagram Marked out of 5.00 1200 P Flag question 1000 800 1000 500 800 600 400 400 200 0.005 0.01 0.015 002 0.025 0.03 0.05 0.1 0.15 Strain (mm/mm) 0.2 0.25 Select one: O E = 1000 Mpa O E= 250 Gpa OE = 120 Gpa E = 50 Gpa E = 200 Gpa Stress (Mpa)
The shear modulus. G. of a material can be determined by applying a torque. T, on a cylindrical material specimen and measuring the angular twist, 0. The modulus can then be calculated from: G each measured variable (L. T.t. 0, R) is 3.4%. 3LT 2 Ree where R and Lare the specimen radius and length, respectively. The relative uncertainty in What is the total relative uncertainty in G? (Provide your amwer as a percentage using two decimal places. Do not include the % symbol.) 1226
. 2) A following figure and table display creep test data obtained from a uniaxial specimen having an initial gauge length of 2 cm. Calculate the steady-state creep rate. Length |(cm) 2.3 Time | (h) 2.25 2.004 2.2 100 2.010 200 2.020 400 2.030 1000 2000 2.045 2.075 2.1 2.05 4000 2.135 6000 2.193 7000 2.230 1.95 8000 2.300 1000 2000 3000 4000 5000 6000 7000 8000 Time (h) (rupture) | Length between the gauge marks (cm) 2.
A tensile test was performed to find the stress-strain curve of a metal sample.Here are the results provided by the tensile testing machine.Suppose the results are free of errors. Elongation, 0 AL (cm) Applied force , F(N) 4.086 5.448 2.724 6.81 1.362 55571.1 61710.1 52930.5 68018.1 39498.3 Additional information : Lo : the length of the extensometer Lo = 5.42 cm A= 5.342 Questions : a) At. Using the 0.2% yield strength method, calculate the tensile strength of the metal sample. b) Find the modulus of resilience of the material under test. c) Calculate the allowable load for an object made of this metal using the parameters following: * Maximum stress: elastic limit Cross section: 10 mm2 Safety factor (or margin): 7 Calculate numerically with a minimum of four decimal places.
16:57 A steel specimen has an original diameter of 0.503 and gage length of 2. You perform a tensile test and acquire the following data: Load (kN) 0 1.5 4.6 8 wamap.org 11 11.8 11.8 12 16.6 20 21.5 19.5 18.5 Elongation (m) 0 0.0005 0.0015 0.0025 0.0035 0.005 0.008 0.02 0.04 0.1 0.28 0.4 0.46 a. Plot the stress-strain diagram on EXCEL (or write MATLAB code to generate the plot). a. Do not calculate stress and strain by hand. In Excel use the function tool: Load (kip Elongation (in) 0 0 1.51 4.6 0.0005 0.0015 Stress Strain 0 =A4/$A$19 23.149 0.00075 If you are using MATLAB, write code to calculate stress and strain. b. Label the x- and y-axes and include units c. Include your name in the filename d. Upload to CANVAS b. Determine the Elastic Modulus, E. c. Read the yield stress off the graph, σy. d. Read the ultimate stress off the graph, ou. e. Read the fracture stress off the graph, of. Round your final answers to 3 significant digits/figures. 1. upload your EXCEL file (or MATLAB…
Q. Based on the calibration curves, find out the respective sensitivities of the displacement measurement. 1. Strain (UE) Strain (UE) 0.01 0.00 -0.01 -0.02 -0.03 -0.04 0.0 0.01 0.00 -0.01 -0.02 0 -0.03 -0.0003-0.0009 -0.04 Strain vs. Displacement (Pushing) -0.0369*x + -3.1E-03 R² = 0.984 0.0 0:0063 -0.011 0.1 0.2 0.3 -0.0152 -0.0049 0.1 0.2 -0.0088 -0.0195 0.3 Strain vs. Displacement (Releasing) -0.0378*x + 2.16E-03 R² = 0.991 -0.0231 -0.0265 -0.0124 -0.0163- 0.4 0.5 0.6 0.7 0.8 0.9 1.0 Displacement (in) -0.02 -0.0298 0.4 0.5 0.6 Displacement (in) -0.0325 -0.0235 0.7 -0.0272 -0.0352 0.8 -0.0379 -0.0318 -0.0379 0.9 1.0
The following data were collected from a 12 mm diameter test specimen of Magnesium. LOAD (N) GAUEGE LENGTH (mm) 0 5000 10000 15000 20000 25000 26500 27000 26500 30.000 25000 30.0296 30.0592 30.0888 30.15 30.51 30.90 31.50 (maximum load) 32.10 32.79 (fracture) After the fracture, the gauge length is 32.61 mm and the diameter is 11.74 mm. a) What is the elastic modulus? b) Percent elongation at fracture? c) Percent elongation after fracture? d) What is the Poisson's ratio? e)Draw the engineering stress-strain diagram corresponding to the values in the table. Call this plot I. Now consider this experiment is repeated at a higher temperature with an identical sample. Draw the new engineering stress-strain diagram, call it plot II and highlight the differences (on the same graph) between I and II.