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Use a similar python code to the first image, to make a double pyramid in the same form as teh second
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THIS CODE IS COMPLETELY DIFFERENT FROM WHAT I ASKED. I NEED A CODE THAT USES A LOOP LIKE WHATS IN THE FIRST IMAGE TO DO EXACTLY WHATS IN THE SECOND IMAGE. PLEASE I DONT WANT MY QUESTION WASTED AGAIN IM BEGGING
- When you perform arithmetic operations with operands of different types, such as adding an int and a float, ____________. C# chooses a unifying type for the result you must choose a unifying type for the result you must provide a cast you receive an error messageDiscrete Mathematics: Assignment details: Replace all the 0 (Zero) digits in your ID by 4. Example: If your ID is 38104680, it becomes 38144684 Take the first 6 digits and substitute them in this expression (( A + B) / C) * ((D-E)/F)-2) according to the following table; Letter Replace by Digit Example Digit A 1st 3 B 2nd 8 C 3rd 1 D 4th 4 E 5th 4 F 6th 6 After substitution your expression will be similar to this (( 3 + 8) / 1) * ((4-4)/6)-2). Draw a rooted tree that represents your expression. What is the prefix form of this expression. 3.What is the value of the prefix expression obtained in step 2 above?#include Servo Main Servo int trigpin = echo pin = 8) opm distance i i Note This Code for Smart Ductoin using Arduino, Sensor & Motor → please give Suplanation about this code int float durahimn float cm Void Setup() Servo Main, allach (7) i Pin Mode (trigpin, output) i Pin Mode (echopin, imput); f void loop() digital write (trigping low) i delay (2); digital write (trigpin, High) ; delay Microsecond (10): digital write / trigpin, low) i duration= Pulse cm = (duration / 5882); distance = Cmi. if (distance (30) { Servo Main write (180), delay (3000) i f else & Servo Mam write (o); delay (50); f In (echopin, High) i
- function triangular_number() { echo "Enter the range of numbers (start end): " read start end even_count=0 odd_count=0 echo "------------------------------------------" for (( i=$start; $i<=$end; i++ )) do triangular=$(( (i*(i+1))/2 )) if [[ $triangular -gt $start && $triangular -lt $end && $((triangular%2)) -eq 0 ]]; then ((even_count++)) echo $triangular elif [[ $triangular -gt $stat && $triangular -lt $end ]]; then ((odd_count++)) fi done echo "------------------------------------------" echo "Total even triangular numbers found: $even_count" echo "Total odd triangular numbers found: $odd_count" } Make a flowchart with this code No hand written and fast answer with explanationJava function to Find whether a given number is a power of 4 or not Example : powerOfFourOrNot(2) -> false powerOfFourOrNot(16) -> truevoid exchangeByValue (int x, int y) { printf ("\n\nOriginal x and y received: $d $d", x, y); int temp; temp =x; x=y; y=temp; printf("\nNew: id $d", x, y): } void exchangeByRef (int *x, int *y) { printf ("\n\nOriginal x and y received: $d $d", *x, *y); int temp; temp = *x; *x = *y; *y = temp; printf ("\nNew: id $d", *x, *y); } а. Show the output b. Trace the output (show the tracing using drawing). Explain your answer if necessary.
- Example: Enter an integer = 75 Smallest divisor is = 3Brute force equation solver this is python program. Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y = -1 have a solution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for x and y in the range -10 to 10. Ex: If the input is: 8 7 38 3 -5 -1 Then the output is: 3 2 Use this brute force approach: For every value of x from -10 to 10 For every value of y from -10 to 10 Check if the current x and y satisfy both equations. If so, output the solution, and finish. Ex: If no solution is found, output: No solution You can assume the two equations have no more than one solution. Note: Elegant mathematical techniques exist to solve such linear equations. However, for other kinds of equations or situations, brute force can be handy. ''' Read in first equation, ax + by = c '''a = int(input())b = int(input())c = int(input()) ''' Read in…e11: Find the value of A for the following: A = (5 + 2* 3+ (( 3-2)* 7)+ -9) /2.
- (-465)10 + (325)10 = ?Using the starter code below, write a program that asks a user for two points (x1, y1) and (x2, y2), then computes the area of the circle for which (x1, y1) is the center and (x2, y2) is on the circle's perimeter. The program should define and use 3 functions: distance(x1, y1, x2, y2): computes and returns the distance between two points • area(r): computes and returns the area of a circle with radius r • main(): asks user for input, calls the other functions, and prints the answer. The input and output of the program should look similar to this: X for center point: 0 Y for center point: 0 X for perimeter point: 1 Y for perimeter point: 1 Area of circle centered at (0.0, 0.0) with radius 1.414213 is 6.283185. Hint 1: Area of a circle = n? Hint2: Distance between 2 points = sqrt(x2-X12 + (Y2 - Y1)²) Starter code: import math def distance(x1, y1, x2, y2): #Add code to compute and return distance between (x1, y1) and (x2, y2) def area(r): #Add code to compute and return area of circle…Python: numpy def serial_numbers(num_players):"""QUESTION 2- You are going to assign each player a serial number in the game.- In order to make the players feel that the game is very popular with a large player base,you don't want the serial numbers to be consecutive. - Instead, the serial numbers of the players must be equally spaced, starting from 1 and going all the way up to 100 (inclusive).- Given the number of players in the system, return a 1D numpy array of the serial numbers for the players.- THIS MUST BE DONE IN ONE LINEArgs:num_players (int)Returns:np.array>> serial_numbers(10)array([1. 12. 23. 34. 45. 56. 67. 78. 89. 100.])>> serial_numbers(12)array([1. 10. 19. 28. 37. 46. 55. 64. 73. 82. 91. 100.])""" # print(serial_numbers(10)) # print(serial_numbers(12))