One mechanism for the destruction of ozone in the upper atmosphere is O3 (9) + NO(9) → NO,(g) + O2 (9) Slow NO2 (9) + O(g) → NO(g) + O2(9) Fast Overall reaction O3(9) + O(g) → 202 (g) a. Which species is a catalyst? 02 O NO2 03 O NO b. Which species is an intermediate? O 02 O NO2 03 O NO c. E, for the uncatalyzed reaction O3 (9) + 0(g) → 20,(9) is 14.0 kJ. E, for the same reaction when catalyzed is11.9 kJ. What is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction at 21°C? Assume the frequency factor A is the same for each reaction. Ratio =

Chemistry for Engineering Students
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Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.28PAE
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One mechanism for the destruction of ozone in the upper atmosphere is
Os (9) + NO(9) → NO,(g) + O2 (9) Slow
NO2 (9) + 0(g) → NO(9) + 02 (9) Fast
Overall reaction O3(9) + O(g) → 20, (9)
a. Which species is a catalyst?
Ο ΝΟ
03
ΟΝΟ
b. Which species is an intermediate?
O 02
O NO2
O 03
ΟΝΟ
c. E, for the uncatalyzed reaction
03 (9) + 0(g) → 20,(g)
is 14.0 kJ. E, for the same reaction when catalyzed is11.9 kJ. What is the ratio of the rate constant for the catalyzed reaction to
that for the uncatalyzed reaction at 21°C? Assume the frequency factor A is the same for each reaction.
Ratio =
Transcribed Image Text:One mechanism for the destruction of ozone in the upper atmosphere is Os (9) + NO(9) → NO,(g) + O2 (9) Slow NO2 (9) + 0(g) → NO(9) + 02 (9) Fast Overall reaction O3(9) + O(g) → 20, (9) a. Which species is a catalyst? Ο ΝΟ 03 ΟΝΟ b. Which species is an intermediate? O 02 O NO2 O 03 ΟΝΟ c. E, for the uncatalyzed reaction 03 (9) + 0(g) → 20,(g) is 14.0 kJ. E, for the same reaction when catalyzed is11.9 kJ. What is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction at 21°C? Assume the frequency factor A is the same for each reaction. Ratio =
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