"ooc-CH, H,C-coo EDTA is a hexaprotic system with the pK, values: pKa1 = 0.00, pK2 = 1.50, pK3 = 2.00, pK„4 = 2.69, pKas = 6.13, and pK = 10.37. N-CH,-CH,-N: "ooc-CH, Hc-coo EDTA (or Y) The distribution of the various protonated forms of EDTA will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, Y*. This fraction is designated ay- . Calculate ayu. at two pH values. pH = 3.85 aya = pH = 10.70 aya =

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
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Chapter9: Atomic Absorption And Atomic Fluorescence Spectrometry
Section: Chapter Questions
Problem 9.6QAP
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EDTA is a hexaprotic system with the pK, values:
"Ooc-CH2
HC-coo
pKal = 0.00, pK2 = 1.50, pK3 = 2.00, pK4 = 2.69,
N-CH,-CH,-N:
pKas = 6.13, and pK6 = 10.37.
"ooc-CH,
H.c-coo
%3D
The distribution of the various protonated forms of EDTA
EDTA- (or Y)
will therefore vary with pH. For equilibrium calculations
involving metal complexes with EDTA, it is convenient to
calculate the fraction of EDTA that is in the completely
unprotonated form, Y. This fraction is designated ayt- .
Calculate ayt- at two pH values.
pH = 3.85
pH = 10.70
aya =
Transcribed Image Text:EDTA is a hexaprotic system with the pK, values: "Ooc-CH2 HC-coo pKal = 0.00, pK2 = 1.50, pK3 = 2.00, pK4 = 2.69, N-CH,-CH,-N: pKas = 6.13, and pK6 = 10.37. "ooc-CH, H.c-coo %3D The distribution of the various protonated forms of EDTA EDTA- (or Y) will therefore vary with pH. For equilibrium calculations involving metal complexes with EDTA, it is convenient to calculate the fraction of EDTA that is in the completely unprotonated form, Y. This fraction is designated ayt- . Calculate ayt- at two pH values. pH = 3.85 pH = 10.70 aya =
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