Answered: orbital period in years

Science

Physics

orbital period in years

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter11: Gravity, Planetary Orbits, And The Hydrogen Atom

Section: Chapter Questions

Problem 21P: Comet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr....

See similar textbooks

Related questions

Q: Which scientist is credited with the collection of data necessary to support the planet's elliptical…

A: The astronomer Tycho Brahe made a series of observations regarding the motion of planets. Kepler,…

Q: Which of the following is NOT one of Kepler's Laws of Planetary Motion? A. The square of a planet's…

A: According to Kepler's first law, Planetary orbits are elliptical with sun as a focus. So, option D…

Q: The figure below shows a planet traveling in a clockwise direction on an elliptical path around a…

A: It is mentioned the planet is rotating in a clockwise direction. With the help of figure and…

Q: Tycho Brahe's observations of the stars and planets were accurate to about 1 arc minute. To what…

Q: Newton showed that the periods and distances in Kepler’s third law depend on the masses of the…

A: We know that Kepler's 3rd Law: The square of the period(T) of a planet's orbit is proportional to…

Q: A planet with mass 8.07x1023 kg orbits a star with mass 1.18x1030 kg. The orbit is circular, and the…

Q: Planet X orbits the star Omega with a "year" that is 650 earth days long. Planet Y circles Omega at…

Q: Why doesn't Earth's rotation provide a suitable time standard?

A: The earth's rotation serves as the foundation for time. Two things will have an impact on the…

Q: A planet with mass 4.83x1023 kg orbits a star with mass 6.95x1030 kg. The orbit is circular, and the…

A: Given Mass of the star is M=6.95×1030 kg Universal gravitational constant is G=6.67×10-11 N.m2/kg2…

Q: Many people mistakenly believe that astronauts that orbit the Earth are "above gravity." Calculate…

A: We know the equation,g = GM/R2

Q: The radius of the Earth's orbit is 1.50 1011 m and that of Mars is 2.28 1011 m. The star that this…

A: The expression for the orbital period,

Q: What does Kepler's third law predict for the period of an Asteroid's orbit around the Sun? Give your…

A: Given data: The value of gravitational constant is G=6.67x10-11 N-m2/kg2. The mass of the asteroid…

Q: A rocket is designed to be launched to space with an acceleration defined by the equation given…

Q: From a distance of 300 km above the surface of the Moon, what is the angular diameter in arc seconds…

A: Given data: Distance above the surface of the Moon, d=300 km=300×103m Linear diameter, x=0.80 m…

Q: A rocket is designed to be launched to space with an acceleration defined by the equation given…

A: We have the acceleration of the rocket which is given by a=-9.81[R2/(R+y)2] where R=6400 km is the…

Q: The first proof that the Earth orbits the Sun was provided by A) Tycho's observations…

A: The first proof that the Earth orbits the Sun was provided by Galileo's observation of the phases of…

Q: An unknown planet (mass is equal to 2.46x 10^29 kg) is orbiting around the sun (mass of the sun is…

Q: If a NASA probe orbits a planet every 1.4 hrs, and its orbit is 11,696.5 km from the center of the…

A: Given, a NASA probe orbits a planet every t=1.4 hrs=1.4×3600=5040 s, and its orbit (circular) is of…

Q: In analyzing distances by applying the physics of gravitational forces, an astronomer has obtained…

Q: Scientists discover a new planet orbiting a distant star. They observe that it takes 1,460 days for…

A: The average distance from planet X to the star is 2.52 × 10^5 m

Q: The arch of a bridge is on the shape of a semi- ellipse having a horizontal span of 94 m and a…

Q: A person's weight W varies inversely as the second power of the distance d from the center of a…

A: As weight varies inversely as the second power of the distance d from centre of the planet we can…

Q: Which of the following statements is correct regarding Kepler's three laws of planetary motion?…

A: Let's check each option one by one Angular momentum of any planet about an axis through the sun and…

Q: The International Space Station (ISS) orbits the Earth once every 7.34 hours. If the radius of the…

A: Gravitational force on ISS by the Earth provides required centripetal force for circular motion of…

Q: Two stars of the same 10*30 kg mass orbit each other at a constant 10*13 meters apart. What is the…

A: The orbital period of the two stars is, T=2πr3GM Here, r is the distance between the stars, G is the…

Q: Find the distance that the earth travels in one day in its path around the sun. Assume that a year…

A: Given data, Earth has a year of 365 days Earth moving in a circle around the sun whose radius is 93…

Q: Assuming that Earth's orbit around the Sun is a circle of radius 150 million kilometres, and taking…

Q: If Jupiter is 5.2 times farther from the sun then earth is. What is the orbital period of Jupiter in…

A: The situation of the planets is shown below. The distance of Jupiter is 5.2 times the distance of…

Q: Predict the time for Mars to orbit around the Sun if the orbital distance of Mars is1.52 times of…

A: Kepler's third law or Law of periods will give the relationship between the period of an orbiting…

Q: The Earth’s radius is about 6370 km. An object that has a mass of 80 kg is taken to a height of 200…

A: Given that an object of mass 80 kg is taken to a height of 200 km from surface of Earth. Te mass of…

Q: The planet Jupiter rotates every 9.9 hours and has a diameter of 88 846 miles. If you’re standing on…

Q: The major axis of the elliptical path in which the earth moves aroundthe sun is approximately…

Q: Planet X has 20 times the mass of the earth and four times the earth's radius. It orbits star Y at a…

A: The given values are,

Q: Planet Smilner circles its star at a distance of 4.76 x 10° km once every 229 Earth years. The…

A: Given: r1 = 4.76 x 109 km = 4.76 x 1012 m T1 = 229 Earth years r2 = 18.7 x 109 km = 18.7 x 1012 m

Q: An unknown planet (mass is equal to 1.29 x 10^12 kg) is orbiting around the sun (mass of the sun is…

A: Mass of the the planet is M1=1.29×1012 kg Mass of the sun is M2=6.623703×1035 kg Gravitational force…

Q: f a planet has an average distance from the Sun of 6.0 AU, what is its orbital period? years

A: To solve this question we need to use Kepler's third law of planetary motion, which state that…

Q: According to Kepler's Law, which of the following statements is true? Explain your work! (a)…

A: solution is given as

Q: The average distance from Earth to the Moon is about 3.84 x 10 to the 5th power and the distance…

A: The average distance from Earth to Moon is, dE,Mo=3.84×105 km The average distance from Earth to…

Q: One full year is 365.26 days. Using this number and the distance between the sun and the earth,…

A: T = 365.26 days

Q: The average distance between Earth and the Sun is 1.5×1011m.1.5×1011m. (a) Calculate the average…

A: Distance between earth and sun=1.5×1011 m Time period to completed 1 revolution around sun = 365.25…

Q: Using the m, = 1.99 x 1030 kg and the mę = 5.98 x 1024 kg and the distance between them as 1.00 AU…

A: The expression for the orbital time period of an object around the Sun is written as, Here, G, Ms,…

Q: Kepler's third law of planetary motion describes a relationship between... the distance from the Sun…

A: Solution: Kepler's first law of planetary motion describes the shape of the orbit of every planet…

Question

100%

The dwarf planet Praamzius is estimated to have a diameter of about 300 km and orbits the sun at a distance of 6.8×10^12m.

What is its orbital period in years?

Express your answer in years to three significant figures.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions

If a planet with 1.5 times the mass of Earth was traveling in Earth’s orbit, what would its period be?
Consider the Earth's orbit around the Sun to be circular with radius R = 9.30 x 107 mi and it takes 365 days to complete one revolution. What is the distance Earth traveled for one revolution (circumference of a circle is 2??2πR )?
A planet with mass 9.69x1023 kg orbits a star with mass 9.21x1030 kg. The orbit is circular, and the distance from the planet to the sun is 225x106 km. What is the length of a year on this planet? Give your answer in earth years (1 earth year = 31,557,600 seconds).
Mars has an orbital radius of 1.523 AU and an orbital period of 687.0 days. What is its average speed v in SI units? (1 AU is the astronomical unit, the mean distance between the Sun and the Earth, which is 1.496×1011 m) a. 0.00221 AU/day b. 3838 m/s c. 0 d. 1.28×10−9 m/s
Two exoplanets, UCF1.01 and UCF1.02 are found revolving around the same star. The period of planet UCF1.01 is 92.4 days, and that of planet UCF1.02 is 7.1 days. If the average distance of UCF1.01 to the sun is 5,828.0 km, what is the average distance of UCF1.02 to the sun in km? Please keep four digits after decimal points.
In a distant star system there are many inhabitable planets. One of these planets is named Qomar. Qomar is 3.2 AU's from its star and takes 6.5 Earth years to go around its star once. There is another planet in the same star system called Ferenginar. Ferenginar is 0.9 AUs from the star. What is the length of a Ferengi year (on Ferenginar) in terms of Earth years?
Mars' period (its "year") was noted by Kepler to be about 687 days (Earth days), which is (687d / 365 d) = 1.88 yr. Determine the distance of Mars from the Sun using the Earth as reference. (The distance of Earth from the Sun is 1.50 x 10 m) !3! Thu TMS IMS TE TES TES TE 2 28 x 10 m TES yr After reading and understanding the concept Gravity, please do the following problems: 1. What keeps a satellite up in its orbit around the Earth?
A new planet is discovered orbiting a distant star. Observations have confirmed that the planet has a circular orbit with a radius of 12 AU and takes 117 days to orbit the star. Determine the mass of the star. State your answer with appropriate mks units. [NOTE: AU ..stands.for...astronomical unit". It is the average distance between Earth & the Sun. 1 AU≈ 1.496 x 1011 m.] Enter a number with units. I be quite large and your calculator will display the answer as a power of 10. If, as an example, your answer was 8.54 x 1056, you would type "8.54e56" into the answer box (remember to state your units with your answer).]
A planet revolves around a star at a distance of 88.5 x 1016 m away from it in a circular orbit. How much distance it travels in half a cycle around that star? Note: Write your answer in scientific representation with two decimal palces. Answer:
A planet’s orbital time period is 29.5 times higher than that of the earth’s orbital period. How far is that planet from the Sun, if the earth is 1.50×108 km away from the sun?
Calculate the angle of (a) 10 (degree) (b) 1′ (minute of arc or arcmin) and (c) 1″(second of arc or arc second) in radians. Use 3600=2π rad, 10 =60′ and1′ = 60 ″
The mean distance of an object A from the Sun is 19.6 x 10^9 km and the mean distance of object B from the Sun is 57.9 × 10^8 km. The period of Earth's revolutions is 1 year, what is the period of object B's revolution?