Part 1 - Determining K, by lon Concentration 9.97 4.03 9.3325 x 10 pH of solution: pOH = 14-pH: JOH] = 100 Complete the following ICE table (using x): Kup Table Mg(OH) (s) Molarity: initial concentration 1 Change Equilibrium concentration Kup Table Molarity: initial concentration Change (-X 0.15580 MB (OH)2 My Complete the following ICE table (now using actual concentrations): Mg(OH), (8) Equilibrium concentration -5 11 Kip [Mg][OH]: Mg (aq) X X + 2 OH(aq) 0 2x 2x Mg (ag) + 2 OH (aq) To find K, use the above ICE table to find the concentration of Mg (you found the concentration of OH above using the pOH). Because there is a 1:2 stoichiometric ratio between Mg" and OH, [Mg] = [OH 1/2. Plug the values of [Mg] and [OH] into the K, expression below: ys 4
Part 1 - Determining K, by lon Concentration 9.97 4.03 9.3325 x 10 pH of solution: pOH = 14-pH: JOH] = 100 Complete the following ICE table (using x): Kup Table Mg(OH) (s) Molarity: initial concentration 1 Change Equilibrium concentration Kup Table Molarity: initial concentration Change (-X 0.15580 MB (OH)2 My Complete the following ICE table (now using actual concentrations): Mg(OH), (8) Equilibrium concentration -5 11 Kip [Mg][OH]: Mg (aq) X X + 2 OH(aq) 0 2x 2x Mg (ag) + 2 OH (aq) To find K, use the above ICE table to find the concentration of Mg (you found the concentration of OH above using the pOH). Because there is a 1:2 stoichiometric ratio between Mg" and OH, [Mg] = [OH 1/2. Plug the values of [Mg] and [OH] into the K, expression below: ys 4
Chapter21: Potentiometry
Section: Chapter Questions
Problem 21.22QAP
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