Part 4: Peppered Moth Allele and Gene Frequencies The dark allele in peppered moths is dominant (B= p). Light moths are homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate the allele and genotype frequencies for peppered moths in year 1 and year 10. Year 1 data: 556 q² = frequency of bb (light) frequency of the dominant allele B is p = 1 Calculate genotypic makeup of the population. [0.054 _(p) + 0.946_(q)]²= 1; 0.232 _(p²) +_ 0.102 (2pq) +0.896_(q²) = 1] Genotypic frequencies are: Year 10 data: 56 q² = frequency of bb (light) 64 _light moths, 0.896 Genotypic frequencies are: dark moths ;q= 0.946 -9; p=1- 0.946 0.002 p² = frequency of BB (dark) 2pq = frequency of Aa (dark) 0.102 q² = frequency of aa(light). 0.896 638 _light moths,_ 0.080 0.282 frequency of the dominant allele B is p = 1 - q; p=1-0.282 _q= dark moths 0.054 0.718 Calculate genotypic makeup of the population. [0.718 (p) + 0.282 (9)1² = 1; 0.847 (p²) + 0.404 (2pq) +0.080 (q²) = 1] p² = frequency of BB (dark) 0.516 2pq = frequency of Aa (dark) 0.404 0.080 q² = frequency of aa(light)

Part 4: Peppered Moth Allele and Gene Frequencies The dark allele in peppered moths is dominant (B= p). Light moths are homozygous recessive (bb= q²). Use the data from Table 1 in Lab 1 to calculate the allele and genotype frequencies for peppered moths in year 1 and year 10. Year 1 data: 556 q² = frequency of bb (light) frequency of the dominant allele B is p = 1 Calculate genotypic makeup of the population. [0.054 _(p) + 0.946_(q)]²= 1; 0.232 _(p²) +_ 0.102 (2pq) +0.896_(q²) = 1] Genotypic frequencies are: Year 10 data: 56 q² = frequency of bb (light) 64 _light moths, 0.896 Genotypic frequencies are: dark moths ;q= 0.946 -9; p=1- 0.946 0.002 p² = frequency of BB (dark) 2pq = frequency of Aa (dark) 0.102 q² = frequency of aa(light). 0.896 638 _light moths,_ 0.080 0.282 frequency of the dominant allele B is p = 1 - q; p=1-0.282 _q= dark moths 0.054 0.718 Calculate genotypic makeup of the population. [0.718 (p) + 0.282 (9)1² = 1; 0.847 (p²) + 0.404 (2pq) +0.080 (q²) = 1] p² = frequency of BB (dark) 0.516 2pq = frequency of Aa (dark) 0.404 0.080 q² = frequency of aa(light)

Name: For the image attached did the moth population evolve? Explain. Is it
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: For the image attached did the moth population evolve? Explain. Is it micro or macroevolution? Part 4: Peppered Moth Allele and Gene FrequenciesThe dark allele in peppered moths is dominant (B= p). Light moths arehomozygous recessive (bb= q²). Use th

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 16RQ: A farmer raises black and white chickens. To his surprise, when the first generation of eggs hatch...

See similar textbooks

Similar questions

Parent Generation BB BB Bb Bb Bb Bb Bb Bb bb bb Rabbits with the brown coat color allele (B) are dominant over rabbits with the white coat color allele (b). A small population of rabbits (Parent Generation) has 2 individuals homozygous for B, 6 individuals that are heterozygous, and 2 individuals homozygous for b. What would you predict the frequencies of alleles B and b to be in the next (first) generation if this population is not evolving Edit View Insert Format Tools Table
Give typing answer with explanation and conclusion What is the expected (predicted) frequency of the A2 allele if it is observed that 26 individual have the homozygous dominant genotype, 62 individuals have the heterozygous genotype and 75 individuals have the homozygous recessive genotype?
Table 5. Composition of F1 generation (Character Wild ΤΟΤΑL number 66 Phenotype Male Female Dominant trait Wild Type 37 29 Recessive trait Tetrapter 9. 9. 18 1. Based on the data shown in Table 5, is it possible to determine the genotypes of all flies showing the dominant trait? Why or why not? 2. Is it possible to determine the genotypes of all flies showing the recessive trait? Why or why not?
Highlight Draw ソeu र In guinea pigs, short hair is dominant over long hair. If a short haired SS guinea pig is erossed with a long haired ss guinea pig, what are the possible genotypes and phenotypes of their offspring and the percent chance of each? 3. S Fill in the table: Genotype Phenotype Chance
I 2. In frost moths, two alleles of one gene determine the character difference of spotted versus striped wings and two alleles of a separate, independent gene determine the character difference of orange wing background versus white wing background. The results for four matings of moth phenotypes are shown below. [Yes - it's possible for the same phenotypes to have different genotypes]. Mating Parental Phenotypes 1 2 3 4 spotted/white x striped/orange spotted/white x striped/orange spotted/orange x striped/ white spotted/orange x striped/orange Spotted/ orange 122 812 422 623 Number of progeny Spotted/ Striped / white orange 131 128 0 430 0 637 a. Determine which alleles are dominant and assign a letter to each. Striped / white 133 0 0 0 b. What are the genotypes of each parent in each cross? If more than one genotype is possible, list the alternative possibilities.
Part 1: Consider three autosomal genes (E, F and G) present in a hypothetical species. The E allele results in male development, the e allele results in female development while the heterozygote develops as a hermaphroditic, sterile individual. The genes at the F and G loci show complete dominance, with the dominant alleles producing long tails (F) and black whiskers (G), while the recessive alleles produce short tails and grey whiskers, respectively. You cross a male with a short tail and black whiskers with a female that has a long tail and black whiskers. All the F1 individuals recovered have long tails, with some having black whiskers and others having grey whiskers. a) What is the sexual phenotype of the F1 offspring? ... b) Another batch of five offspring are expected from the same parents. What is the probability of the first offspring having a long tail and black whiskers?
Let’s suppose that pigmentation in a species of insect is controlledby a single gene that exists as two alleles, D for dark and d for light.The heterozygote, Dd, is intermediate in color. In a heterogeneousenvironment, the allele frequencies are D = 0.7 and d = 0.3. Thispolymorphism is maintained because the environment has somedimly lit forested areas and some sunny fields. During a hurricane,a group of 1000 insects is blown to a completely sunny area. In thisenvironment, the relative fitness values are DD = 0.3, Dd = 0.7, anddd = 1.0. What are the predicted allele frequencies in thenext generation?
Table 14. Crossing Fl individual with another Fl individual Individual # 213 252 Gender Male Female Wild Type Wings Wild Type Antenna Aristapedia Wings Wild Type Antenna Phenotype Table 15. Composition of F2 generation Character 1: No. of Males No. of ΤΟΤAL Females number Wing Veins Antennae Cleft Cleft Wild Type Wild Type Aristapedia 16 12 Wild Type 9 11 1 10 Aristapedia 11 22 Wild Type 13 15 28 1. Does a trait always go together with another trait in one individual? Yes or No? If yes, identify the traits that go together. If no, explain why not? 2. Based on the data in Table 15, what are the possible genotypes of the FI individuals thal you crossed (see Table 14)? Male parent: Female parent: Phenotypes
Imagine a locus with two alleles. Mutation at this locus changes one allele to the other (i.e. it does not create a new allele). If the rate of mutation from allele 1 to allele 2 is 0.00005 and the rate of mutation from allele 2 to allele 1 is 0.01, what is the equilibrium frequency of allele 2 (Give your answer to 5 decimal places)?
In a randomly mating population of Drosophila, 16% of the flies have black bodies (an autosomal, recessive trait) and 84% have brown bodies. This population is assumed to be in Hardy-Weinberg equilibrium. 6. If a researcher samples 10 000 Drosophila from this population, the number of flies expected to be homozygous dominant for body colour is 8 400 1600 3 600 4 800 Congenital myasthenic syndrome (CMS) is an autosomal recessive disorder that is found in a higher-than-normal frequency in a Roma population in Europe. Researchers examined 43 people for CMS in the population and found that 13 of them had the disorder. 11. What is the frequency of the CMS disorder in the Roma population examined by the researchers? Answer: (Record your answer as a value rounded to two decimal places in the numerical-response section on the answer sheet.) The number of deer in a 15 080 km² area of Northern Alberta was 670 in 2008. In 2018, the number of deer in the same area was 552. 13. The per capita…
Hardy-Weinberg Problem; The frequency of the dominant phenotype, brown (B) coat coloris 73% in a population of 1032 mice. The recessive condition is white fur (b). Determine the following and show all work: Frequency of the white genotype in the population Percentage of the population with the genotype BB Number of mice that are heterozygous Frequency of the gominant allels. Number of recessive alleles in the population
A farmer raises black and white chickens. To his surprise, when the first generation of eggs hatch all the chickens are black with white speckles throughout their feathers. What should the farmer expect when the eggs laid after interbreeding the speckled chickens hatch? All the offspring will be speckled 75% of the offspring will be speckled, and 25% will be black 50% of the offspring will be speckled, 25% will be black, and 25% will be white 50% of the offspring will be black and 50% of the offspring will be white.