Pedigree 2: A. What is the most likely mode of inheritance of this disease? Choose from: autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive. B State the genotypes of individuals # 1- #4. 4. C. If individual #3 has another daughter with the same partner, what is the probability that this daughter will be affected (show the disease)?
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- Complete the following queatione BEFORE ATTEMPTING THE HW 1 BLACKBOARD ASSIGNMENT, In the following human pedigrees, the filled symbols represnent the affected individuals who suffer from the disease. Use A/a to represent alleles for autosomal traits and XIX/Ytorepresent alleles for X-linked traits. Use the uppercase letter to represent the dominant allele and the lowercase letterto represent the receasive allele. afected fomale Unafected female affected male Unaffected male Pedigree 1: A. What is the most likely mode of inheritance of this disease? Choose from: autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive. B. State the genotypes of individuals #1-#3. C. What is the probability that individual #4 is a carrier of this disease if his mother is homozygous dominant and his father is heterozygous? Pedigree 2: What is the most likely mode of inhentance of this disease? Choose from: autosomal dominant, autosomal recessive X-linked dominant X-linked recessive.…b. The following diagram shows a family tree of individuals with haemophilia. B i. Based on an X-linked recessive pattern of inheritance, work out the likely genotypes of the individuals indicated by the letters. Individual A Individual B Individual C GENOTYPE ii. If individual C has children with a normal male, what are the chances that they will have haemophilia? Explain your answer fully. iii. If individual C has children with a normal male, what are the chances that their daughters will be carriers of the condition? Explain your answer fully.3) State whether each of the following genetic defects is inherited as an autosomal recessive, autosomal dominant, or X-linked recessive trait: phenylketonuria (PKU), sickle cell anemia, cystic fibrosis, Tay-Sachs disease, Huntington’s disease, and hemophilia A.
- AaBbCcDc AaBbCcD Ac Heading 1 Heading 2 Title Subtitle Subtle Em.. Emphasis Intense E... Strong Quote Int Paragraph Styles 4 Genetic Inheritance Patterns Retinitis pigmentosa (RP) can be autosomal recessive, autosomal dominant, or x-linked. Apparently the dominant forms are often less severe. Eric's form of RP is Usher's Syndrome, which is an autosomal recessive inheritance (i.e., you must get a copy of the defective carried on one of the chromosomes that determines sex. Usher's Type II is recessive, so for Eric this means that both his Mom and Dad are carriers of this condition. His brother, Dirk, does not have any symptoms of RP. gene from your Mom and one from your Dad). Autosomal means it is not Question below short answer approach image you are the genetics counselor, should Eric have children? Imagine he has a daughter (he has two, but both are adopted). What advice would you give Eric if his wife was a carrier from a genetics counseling viewpoint? Describe all the possibilities,…a. The ability to taste the chemical phenylthiocarbamideis an autosomal dominant phenotype, and the inabilityto taste it is recessive. If a taster woman with a nontasterfather marries a taster man who in a previous marriagehad a nontaster daughter, what is the probability thattheir first child will be(1) A nontaster girl(2) A taster girl(3) A taster boyb. What is the probability that their first two childrenwill be tasters of either sex?D. Sex-linked In humans, hemophilia is a sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won't ever be carriers). 1. Show the cross of a man who has hemophilia with a normal woman. What is the probability that their children will have the disease? H H = female, normal H h X X = female, carrier h xxn XHY X" Y 2. A woman who is a carrier marries a hemophiliac man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be? 3. A woman who has hemophilia marries a normal man. How many of their children will have hemophilia, and what is their sex? = female, hemophiliac = male, normal = male, hemophiliac
- 12. A. B. C. A certain type of migraine headache (M) is dominant to no migraines (m). What is the genotype of a man who has migraine headaches if his father did not have them? What is the genotype of a man who has migraine headaches if his mother did not have them? If a woman without migraines marries a man who is heterozygous for migraines, what would you expect for the genotypes and phenotypes of their children? If two people who are heterozygous for migraines marry and have children, what would you expect for the genotypes and phenotypes of the children.II. Given the following pedigree below, use Punnett squares for each of the following possibilities: a) Autosomal recessive and b) Autosomal dominant in order to determine what is the mode of transmission of this trait. Disease allele = a or A, depending on mode of transmission of the disease respectively. Your Punnett squares should reflect what you see in generation II. Circle the mode of transmission. Note: Observe the whole pedigree. I Circle the mode of transmission 1 III 6 genotype (circle one): AA Created by Dr. Susan A. Holechek for BIO 340 (2023) 2 1 2 3 4 a) Autosomal recessive 11 x 12 9 XªXa 2 3 5 6 Ở хаха *4 7 b) Autosomal dominant 11x12 8 Aa *Unaffected/No carrier-Normal AaAaWhile studying of the family tree with history of hypertrichosis (hyper hirsutism of the ear) this sign was founded only in the men and it was inherited from father to the son. Define the type of hypertrichosis inheritance? Select one: a. Y-linked b. Autosomal-recessive O c. Autosomal-dominant d. Recessive, X-linked e. Dominant, X-linked
- Explain the sex-linked traits. (S9LT-ld-29.4.4) Solve problems related to sex-linked traits. (S9LT-ld-29.4.4) WHAT I NEED (MATERIALS) • Worksheet • Pens WHAT TO DO (PROCEDURE) PART A Directions: Tell whether the following carry or show the sex-linke recessive spongy-tiny pores trait. Also, tell whether the individuals a male or female. Remember that since most sex-linked traits are recessive, the person w shows the trait can have no X's with big superscripted letters. So, if a m carries the trait, he must also show the trait. XDY XDXD XdY Carrier? (Yes or No) Has the Trait? (Yes or No) Male or Female Phenotype or Appearance of the Individual ided Questions: 1. What chromosomes will result to a normal phenotype (normal spongy po trait12tion 8: below is the pedigree of inheritance of phenylketonuria (PKU). We will designate the letter Caven for the dominant allele and "p" for the recessive allele. 4 The pedigree shows that the pattern of inheritance for the allele for phenylk ylketonuria is: I. II. 1 III. IV. Autosomal dominant Autosomal recessive X-linked dominant X-linked recessive b. The parents in generation I have how many children: I. 3 Boys II. 3 Girls III. IV. 3 Boys and 1 Girl 3 Girls and 1 Boy c. What is the genotype of individual 1 in generation III: I. PP II. pp III. Pp " O 1 III. 50% E III 1 ▬ 2 2 IV. 25% 1 3 IV. Can be PP or Pp ii. Suppose that a man having type AB blood marries a woman having type O blood. What is the probability that their child will have type A blood? I. 100% II. 75% 2 4 3Ill.siven the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked dominant, b) X-linked recessive, c) Autosomal dominant and d) Autosomal recessive in order to determine what is the mode of transmission of this trait. Disease allele = Xª, x², A or a depending on mode of transmission of the disease respectively. Unaffected X chromosome = X *Homozygous unaffected/No 1 *2 carrier=Normal II 1 *4 1 2 3 6. 7 8 a) X-linked dominant 11x12 b) X-linked recessive I 1 x1 2 c) Autosomal dominant 11x12 d) Autosomal recessive I1x12 IV. Based on your analysis what is the mode of transmission for this disease? O+