Aktiv Chemistry← → Ctabshift+esccaps lockXhttps://app.101edu.co!Aktiv Chemistry40%Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene(C₂H₁) according to the following reaction:8C₂H₁(1) + O₂(g) + NH₂(g) → C₂H₂N₂(s) + H₂O(l)8108 4How many moles of water would be produced by the completeammoxidation of 130.0 grams of o-xylene?2F2NWS#320F3EX30$4X +D8888F4RCLO LO%5FF5TQuestion 12 of 17VGY7F7HBU00DIIF8JF9K4N M+/-1770IF10

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Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene (CH) according to the following reaction: CH (1) + O₂(g) + NH₂(g) →→ C₂H₂N₂(s) + H₂O(l) How many moles of water would be produced by the complete ammoxidation of 130.0 grams of o-xylene? 1 4

Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene (CH) according to the following reaction: CH (1) + O₂(g) + NH₂(g) →→ C₂H₂N₂(s) + H₂O(l) How many moles of water would be produced by the complete ammoxidation of 130.0 grams of o-xylene? 1 4

Chemistry: The Molecular Science

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Chapter10: Fuels, Organic Chemicals, And Polymers

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Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to as solute. Solution chemistry plays an important role in chemistry since it supports many commercial applications of solutions.

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Aktiv Chemistry
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Phthalonitrile (CHN) is produced by the ammoxidation of o-xylene
(C₂H₁) according to the following reaction:
8
C₂H₁(1) + O₂(g) + NH₂(g) → C₂H₂N₂(s) + H₂O(l)
8
10
8 4
How many moles of water would be produced by the complete
ammoxidation of 130.0 grams of o-xylene?
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