Answered: Please explain question 2 2.In mice…

Name: Please explain question 2 2.In mice the autosomal genotype yy is for g
Uploaded: 2024-03-20T06:42:55.000Z
Channel: Bartleby
Description: Please explain question 2 2.In mice the autosomal genotype yy is for gray fur, YY is for brown fur and Yy is for yellow fur. What is the ratio of offspring from the cross between two yellow mice?

Science

Biology

Please explain question 2 2.In mice the autosomal genotype yy is for gray fur, YY is for brown fur and Yy is for yellow fur. What is the ratio of offspring from the cross between two yellow mice?

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 24CTQ: Mendel performs a cross using a true-breeding pea plant with round, yellow seeds and a true-...

See similar textbooks

Similar questions

3) In the snail Capaea nemoralis, an autosomal allele causing a banded shell (B®) is recessive to the allele for an unbanded shell (B°). Genes at a different locus determine the background color of the shell; here yellow (C') is recessive to brown (CBw). A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a test cross). a. What will the results of the testcross be in the loci that control banding and color ARE linked with NO crossing over.
3) In the snail Capaea nemoralis, an autosomal allele causing a banded shell (B³) is recessive to the allele for an unbanded shell (B°). Genes at a different locus determine the background color of the shell; here yellow (C) is recessive to brown (CB"). A banded, yellow snail is crossed with a homozygous brown, unbanded snail. The F1 are then crossed with banded, yellow snails (a test cross). С. What will the results be of the testcross if the loci ARE linked and 20 m.u. apart?
2. a. A Drosophila male from a true-breeding stockwith scabrous eyes was mated with a female from atrue-breeding stock with javelin bristles. Both scabrous eyes and javelin bristles are autosomal recessive mutant traits. The F1 progeny all had normaleyes and bristles. F1 females from this cross weremated with males with both scabrous eyes andjavelin bristles. Write all the possible phenotypicclasses of the progeny that could be produced from the cross of the F1 females with the scabrous, javelin males, and indicate for each class whether it is arecombinant or parental type.b. The cross in part (a) yielded the following progeny:77 scabrous eyes and normal bristles; 76 wild type(normal eyes and bristles); 74 normal eyes andjavelin bristles; and 73 scabrous eyes and javelinbristles. Are the genes governing these traits likelyto be linked, or do they instead assort independently? Why?c. Suppose you mated the F1 females from the crossin part (a) to wild-type males. Why would thiscross fail…
Mendelian Genetics [6F.R]:Question 1 In rabbits, grey fur (G) is dominant to white fur (g) and black eyes (B) are dominant to red eyes (b). A male rabbit with the genotype GgBb is crossed with a female rabbit with the genotype ggbb. What percent of the offspring will have white fur and red eyes? Select one: 25% 50% 100% 0% 1000
Assuming a pure-breeding P generation, what ratio would you expect in the F2 generation if a mutant phenotype is inherited in an autosomal recessive fashion? (remember, F1 are intercrossed) O 3 wildtype:1 mutant O 75% mutant and 25% wildtype O 1 mutant female : 1 mutant male: 1 wildtype female : 1 wildtype male O 50% mutant: 25% wildtype : 25% mutant, wildtype O All F2 will be mutant
SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b plant color booster vs. non-booster +/lg with ligule vs. without ligule +/v green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg + + lg 305 148 58 bv + + + + 62 + v + b + + 152 275 1000 Total Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.
SET 2: In corn, the following allelic pairs have been identified in chromosome 3: +/b > plant color booster vs. non-booster +lg → with ligule vs. without ligule +/v > green plant vs. virescent A test cross between triple recessive plants and plants heterozygous for the three pairs gave the following progeny: + v lg b + lg b v lg 305 148 58 + + lg b v + + + + 62 + v + 152 b + + 275 Total 1000 Calculate the parental and recombinant frequencies, the map distances between genes, and the coefficient of coincidence. Illustrate the gene map or sequence.
43. Two pea plants are crossed. Each is heterozygous for height (T=tall, t= dwarf) and purple flowers (P = purple flowers, p=white flowers). What percentage of the offspring will be dwarf and white? phenotypic ratio Was it necessary to complete a Punnett square to answer this question? Explain.
In the F2 generation of this cross, 224/300 embryos develop into wild-type flies, while 76/300 of embryos display the lethal no head phenotype. 3. What are the F2 phenotype ratios?
3)Mendel found that crossing wrinkle-seeded (rr) plants with homozygous round-seeded(RR) plants produced only round-seeded plants. What genotype ratio and phenotyperatio can be expected from a cross between a wrinkle-seeded plant and a heterozygousplant for this characteristic?
2/2 - A heterozygous black haired male hamster is crossed with a heterozygous black haired female hamster. Give the genotypic and phenotypic ratios of the offspring. If they had 12 babies, how many would you expect to be white? 10. Key Parents: Punnett Sqare: B%3= b- BB: Bb: bb Genotypic Ratio: black: white Phenotypic Ratio: It they had 12 babies, how many would vou expect to be white?
What is the correct table in these two given? 1. Take two coins and assume that heads represent the dominantallele (A) and tails represents the recessive allele (a). The genotype for each coin isheterozygous (Aa).2. Assume that each coin represents one parent. When a single coin is flipped, one gameteis formed (through the process of meiosis). If the flipped coin is on heads, then thegamete has the dominant allele (A). When both coins are flipped simultaneously, therewill be two possible gametes that can combine through fertilization to form a zygote. Eachtime you flip both coins, you will record the “genotype” of the offspring.3. Flip the coins 100 times and record your results in the chart below