Please use Python for this problem.

Make sure code is in correct format so it can run in Python without any errors and has the correct answer:

Submit a single file named hw7.py that contains the solutions to the two problems below. When you are finished, test your solutions using doctest.

Include the following code at the bottom of your module in order to run the doctest:

if __name__=='__main__':

    import doctest

    print( doctest.testfile( 'hw7TEST.py'))

Develop a class Volume that stores the volume for a stereo that has a value between 0 and 11. Usage of the class is listed below the problem descriptions. Throughout the class you must guarantee that:

The numeric value of the Volume is set to a number between 0 and 11. Any attempt to set the value to greater than 11 will set it to 11 instead, any attempt to set a negative value will instead set it to 0.

This applies to the following methods below: __init__, set, up, down

You must write the following methods:

__init__ - constructor. Construct a Volume that is set to a given numeric value, or, if no number given, defaults the value to 0.   (Subject to 0 <= vol <=11 constraint above.)

__repr__ - converts Volume to a str for display, see runs below.

set – sets the volume to the specified argument (Subject to 0 <= vol <=11 constraint above.)

get – returns the numeric value of the Volume

up – given a numeric amount, increases the Volume by that amount. (Subject to 0 <= vol <=11 constraint above.)

down – given a numeric amount, decreases the Volume by that amount. (Subject to 0 <= vol <=11 constraint above.)

__eq__ - implements the operator ==.   Returns True if the two Volumes have the same value and False

Output for this function:

# hw7TEST.py

# set and get

>>> v = Volume()
>>> v.set(5.3)
>>> v
Volume(5.3)
>>> v.get()
5.3
>>> v.get()==5.3 # return not print
True
>>> v.set(13.2)
>>> v
Volume(11)
>>> v.set(-1.2)
>>> v
Volume(0)

# __init__, __repr__, up, down

>>> v = Volume(4.5) # set Volume with value
>>> v
Volume(4.5)
>>> v.up(1.4)
>>> v
Volume(5.9)
>>> v.up(6) # should max out at 11
>>> v
Volume(11)
>>> v.down(3.5)
>>> v
Volume(7.5)
>>> v.down(10) # minimum must be 0
>>> v
Volume(0)

# default arguments for __init__

>>> v = Volume() # Volume defaults to 0
>>> v
Volume(0)

# can compare Volumes using ==

>>> # comparisons
>>> v = Volume(5)
>>> v.up(1.1)
>>> v == Volume(6.1)
True
>>> Volume(3.1) == Volume(3.2)
False

# constructor cannot set the Volume greater
# than 11 or less than 0

>>> v = Volume(20)
>>> v
Volume(11)
>>> v = Volume(-1)
>>> v
Volume(0)
>>>

# more thorough checks of clamping

>>> v = Volume()
>>> [ (val*.5,v.set(val*.5),str(v)) for val in range(-3,30,4)] # set
[(-1.5, None, 'Volume(0)'), (0.5, None, 'Volume(0.5)'), (2.5, None, 'Volume(2.5)'), (4.5, None, 'Volume(4.5)'), (6.5, None, 'Volume(6.5)'), (8.5, None, 'Volume(8.5)'), (10.5, None, 'Volume(10.5)'), (12.5, None, 'Volume(11)'), (14.5, None, 'Volume(11)')]
>>> [ (val*.5,Volume(val*.5)) for val in range(-3,30,4)] # constructor
[(-1.5, Volume(0)), (0.5, Volume(0.5)), (2.5, Volume(2.5)), (4.5, Volume(4.5)), (6.5, Volume(6.5)), (8.5, Volume(8.5)), (10.5, Volume(10.5)), (12.5, Volume(11)), (14.5, Volume(11))]
>>> v = Volume(5)
>>> [ (v.up(.75), str(v)) for i in range(10) ] # up
[(None, 'Volume(5.75)'), (None, 'Volume(6.5)'), (None, 'Volume(7.25)'), (None, 'Volume(8.0)'), (None, 'Volume(8.75)'), (None, 'Volume(9.5)'), (None, 'Volume(10.25)'), (None, 'Volume(11.0)'), (None, 'Volume(11)'), (None, 'Volume(11)')]
>>> v = Volume(5)
>>> [ (v.down(.75), str(v)) for i in range(10) ] # down
[(None, 'Volume(4.25)'), (None, 'Volume(3.5)'), (None, 'Volume(2.75)'), (None, 'Volume(2.0)'), (None, 'Volume(1.25)'), (None, 'Volume(0.5)'), (None, 'Volume(0)'), (None, 'Volume(0)'), (None, 'Volume(0)'), (None, 'Volume(0)')]
>>>

Question

Please use Python for this problem.

Make sure code is in correct format so it can run in Python without any errors and has the correct answer:

Submit a single file named hw7.py that contains the solutions to the two problems below. When you are finished, test your solutions using doctest.

Include the following code at the bottom of your module in order to run the doctest:

if __name__=='__main__':

import doctest

print( doctest.testfile( 'hw7TEST.py'))

Develop a class Volume that stores the volume for a stereo that has a value between 0 and 11. Usage of the class is listed below the problem descriptions. Throughout the class you must guarantee that:
- The numeric value of the Volume is set to a number between 0 and 11. Any attempt to set the value to greater than 11 will set it to 11 instead, any attempt to set a negative value will instead set it to 0.
- This applies to the following methods below: __init__, set, up, down

You must write the following methods:

__init__ - constructor. Construct a Volume that is set to a given numeric value, or, if no number given, defaults the value to 0. (Subject to 0 <= vol <=11 constraint above.)
__repr__ - converts Volume to a str for display, see runs below.
set – sets the volume to the specified argument (Subject to 0 <= vol <=11 constraint above.)
get – returns the numeric value of the Volume
up – given a numeric amount, increases the Volume by that amount. (Subject to 0 <= vol <=11 constraint above.)
down – given a numeric amount, decreases the Volume by that amount. (Subject to 0 <= vol <=11 constraint above.)
__eq__ - implements the operator ==. Returns True if the two Volumes have the same value and False

Output for this function:

# hw7TEST.py

# set and get

>>> v = Volume()
>>> v.set(5.3)
>>> v
Volume(5.3)
>>> v.get()
5.3
>>> v.get()==5.3 # return not print
True
>>> v.set(13.2)
>>> v
Volume(11)
>>> v.set(-1.2)
>>> v
Volume(0)

# __init__, __repr__, up, down

>>> v = Volume(4.5) # set Volume with value
>>> v
Volume(4.5)
>>> v.up(1.4)
>>> v
Volume(5.9)
>>> v.up(6) # should max out at 11
>>> v
Volume(11)
>>> v.down(3.5)
>>> v
Volume(7.5)
>>> v.down(10) # minimum must be 0
>>> v
Volume(0)

# default arguments for __init__

>>> v = Volume() # Volume defaults to 0
>>> v
Volume(0)

# can compare Volumes using ==

>>> # comparisons
>>> v = Volume(5)
>>> v.up(1.1)
>>> v == Volume(6.1)
True
>>> Volume(3.1) == Volume(3.2)
False

# constructor cannot set the Volume greater
# than 11 or less than 0

>>> v = Volume(20)
>>> v
Volume(11)
>>> v = Volume(-1)
>>> v
Volume(0)
>>>

# more thorough checks of clamping

>>> v = Volume()
>>> [ (val*.5,v.set(val*.5),str(v)) for val in range(-3,30,4)] # set
[(-1.5, None, 'Volume(0)'), (0.5, None, 'Volume(0.5)'), (2.5, None, 'Volume(2.5)'), (4.5, None, 'Volume(4.5)'), (6.5, None, 'Volume(6.5)'), (8.5, None, 'Volume(8.5)'), (10.5, None, 'Volume(10.5)'), (12.5, None, 'Volume(11)'), (14.5, None, 'Volume(11)')]
>>> [ (val*.5,Volume(val*.5)) for val in range(-3,30,4)] # constructor
[(-1.5, Volume(0)), (0.5, Volume(0.5)), (2.5, Volume(2.5)), (4.5, Volume(4.5)), (6.5, Volume(6.5)), (8.5, Volume(8.5)), (10.5, Volume(10.5)), (12.5, Volume(11)), (14.5, Volume(11))]
>>> v = Volume(5)
>>> [ (v.up(.75), str(v)) for i in range(10) ] # up
[(None, 'Volume(5.75)'), (None, 'Volume(6.5)'), (None, 'Volume(7.25)'), (None, 'Volume(8.0)'), (None, 'Volume(8.75)'), (None, 'Volume(9.5)'), (None, 'Volume(10.25)'), (None, 'Volume(11.0)'), (None, 'Volume(11)'), (None, 'Volume(11)')]
>>> v = Volume(5)
>>> [ (v.down(.75), str(v)) for i in range(10) ] # down
[(None, 'Volume(4.25)'), (None, 'Volume(3.5)'), (None, 'Volume(2.75)'), (None, 'Volume(2.0)'), (None, 'Volume(1.25)'), (None, 'Volume(0.5)'), (None, 'Volume(0)'), (None, 'Volume(0)'), (None, 'Volume(0)'), (None, 'Volume(0)')]
>>>

Accepted Answer

Solution:

Defining the constructor which takes  two volumes  if value is not given then set one of…