Problem 2. An unknown substance has a density of 8.8 g/cm³ and atomic radius of 0.145 nm. It crystallizes to form a body-centered cubic unit cell. Determine its molar mass.
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- Question 5 2 Points Europium forms a body-centered cubic unit cell and has an edge length of 4.68 cm. From this information, determine the atomic radius. A 9.36 cm B) 2.03 cm 13.24 cm 6.62 cm DI2 Body-Centered Unit Cell (b) Fig 5. Body-Centered Cubic (BCC) Unit Cell. (a) Ball-and-Stick Model (b) Space-filled Model (c) Stacking (a) (c) a. How many unit cells share the center atom of the body-centered unit cell? Answer: b. How many total atoms are there in a body centered cubic cell? Answer:Problem 1. (a) What is the atomic radius (in nm) of a certain metal particle if it crystallizes with a face-centered cubic unit cell 0.32 nm on an edge? (b) What will be its theoretical density if it has an atomic weight of 88.9 g/mol? Problem 2. An unknown substance has a density of 8.8 g/cm³ and atomic radius of 0.145 nm. It crystallizes to form a body-centered cubic unit cell. Determine its molar mass.
- Hint The density of solid W is 19.3 g/cm³. How many atoms are present per cubic centimeter of W? Number 0 atoms/cm³ As a solid, W adopts a body-centered cubic unit cell. How many unit cells are present per cubic centimeter of W? Number unit cells/cm³ What is the volume of a unit cell of this metal? Number cm³ What is the edge length of a unit cell of W? Number cm Previous Give Up & View Solution Check AnswerProblem 4. Platinum, with an atomic weight of 195.1 g/mol, has a density of 21.45 g/cm³ and a unit cell with an edge length of 393 pm. What is its (a) unit cell structure and (b) atomic radius (in pm)? Problem 5. A certain metal forms a cubic unit cell with a volume of 0.061 nm³. Determine its geometry if it has an atomic radius of 196 pm.Cr crystallizes in a body-centered cubic lattice. The atomic radius of Cr is 128 pm. Calculate the unit cell edge length in angstrom (Å). (Conversion factors: 1 m = 1 x 1012 pm; 1 m = 1 x 1010 Å) A) 1.28 Å B) 3.62 Å c) 2.54 Å D) 2.96 Å
- Cr crystallizes in a body-centered cubic lattice. The atomic radius of Cr is 128 pm. Calculate the unit cell edge length in angstrom (Å). (Conversion factors: 1 m = 1 x 1012 pm; 1 m = 1 x 1010 A A 2.54 A B 2.96 Å 3.62 Å (D) 1.28 Å3. What is the relationship between edge length (a) and atomic radius (r)? Answer: Type of cubic unit cell Simple cubic Body-centered cubic Relationship between a and r a = 2r 4r a = - V3 Face-centered cubic a = V8 rMetallic barium crystallizes in a body-centered cubic lattice, with one Ba atom per lattice point. If the metallic radius of Ba is 217 pm, what is the volume of the unit cell in pm³ and in cm³? 3 pm³ 3 cm³. Please type answer no write by hend.
- Provide STEP by STEP details correct Explanation. Question : iron has a face centered cubic unit cell with a length of 608 pm along an edge. what is the density of iron in kg m-3 .iClicker Question: Vanadium (V) crystallises in a bcc structure and has an atomic radius of 131 pm. Determine the density if the edge length of the bcc unit cell is 4r/v3 and the atomic mass is 50.94 g/mol. (NA = 6.022×1023 mol-1) A. 3.06 g/cm3 B. 6.11 g/cm3 C. 2.77 g/cm3 D. 12.2 g/cm3 E. 8.46 g/cm3PROBLEM SE C 48. Barium crystallizes in a bcc lattice with barium atoms only at the lattice points. If the density of barium 3.50 g/cm³, what is the length of the unit cell? A. 3.19x108 cm B. 4.02x10 cm C. 5.07x108 cm D. 6.39x108 cm