Problem 7-25: Determine the maximum shear stress acting at section a-a of the cantilevered strut. 250 mm- -250 mm 1 2 kN 4 kN 20 mm 300 mm- 70 mm 20 mm 50 mm
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- s after the decimal po 200mm b18010 300mm L2 Joint D b18010 L1 "p double AR shear b180106003-1892615 B 50mm b18010 - 30mm b180106003-18926151 A frame is given above and an external load R is applied at point C. Pin connection Joint B b18010 b180106003- 18926151126 dg b1801000s Calculate the maximum normal stress for member BD by taking into account the reduced sectional areas at the pin connections. b180106003- 18926151126 (dD= 8mm, single shear b18010 b180108003-18926151126 at Dis in double shear, B is in single shear. b180106003-18926151126 b180106003 151126 24,05 MPa A b18010 18926151126 31,37 MPa b180106003 -18926151126 18926151126 01000s-18926151126 37,04 MPa b180108003-18926151126 b18010 828 18926151126 43,73 MPa bi8010 b180108003- 18928151126 b180106003-18926151126 18926151126 b180106003- 18926151126 b180100003-18926151126 b180106003- 18926151126 b180100003-18926151126 b18010 b180108003-18926151126 b180108003-18926151126 b18010950 mm is employed to compress à 6061-T6 aluminum 650 mm as shown. The tie rod has a solid circular cross section with A solid 4340 HR Steel tie rod of length Lrod bushing of length Lbushing diameter drod do - = = 27.5 mm. The bushing has a hollow circular cross section with outer diameter 80 mm, inner diameter di, and wall thickness t. If F = 47.5 kN, determine the minimum wall thickness of the bushing based on the below design requirements: ⚫ the displacement of the bottom of the tie rod with respect to the fixed horizontal surface may not exceed total = 1.1 mm ⚫ the normal stress of the bushing may not exceed the yield strength of the bushing material tmin Lbushing do Lrod = 7.056 drod F Rod cross section drod Bushing cross section mm X 0% do diUse the graphical method to construct the shear-force diagram and identify the magnitude of the largest shear force (consider both positive and negative). The ground reactions at the wall of the cantilever are provided. L₁= 14.75 ft L₂ = 7.75 ft Vc = 91.50 kips Mc = 706.4375 kip-ft 20 kips 6 kips/ft L₁ 103.50 kips 68.50 kips 91.50 kips O 79.50 kips O 114.50 kips 70 kips BO 12 kips/ft L2 O Vc Mc
- Direct a key d the Hub Shear plane Hub Key F2 y, or anical F1 T=Torque Shaft T=F(D/2) F = Force of shaft on key F= Force of hub on key Side view -D Shaft diameter End view Shear Shaft plane Hub F1 Key F2 Shear area = A, = bxL %3D Enlarged view of key Pictorial sketch of key, shaft, and hub НоуPROBLEM 6/6 F = 520 kN Determine the stress in each aluminum and steel bars after 0.2 mm F = 520 kN is applied. Note that a gap of 0.2 mm exist before the external load is Steel 280 mm applied and bars has equal distance with each other. Neglect the weight at the flat form. A = 1100 mm2 E = 200 Gpa A = 2500 mm² E = 70 GPa Steel AluminumUse the graphical method to construct the shear-force diagram and identify the magnitude of the largest shear force (consider both positive and negative). The ground reactions at the wall of the cantilever are provided. L₁= 14.00 ft L2= 7.75 ft Vc = 87.00 kips Mc = 621.875 kip-ft 20 kips 6 kips/ft L₁ 64.00 kips 99.00 kips 110.00 kips 87.00 kips O 75.00 kips 70 kips B 12 kips/ft L2 Vc Mc
- Example Problem: 4-31 (modified) The concrete column is reinforced using four steel reinforcing rods, each having a diameter of 18 mm. Determine the stress in the concrete and the steel if the column is subjected to an axial load of 800 KN. EST= 200 GPa and Ec = 25 GPa. Represent the stress in each with a volume element. 300 mm 800 KN 300 mm5-126* A short standard-weight steel pipe (see Appendix B) is used to support an axial compressive load of 100 kN. If yield- ing (o, = 250 MPa) should not occur and the factor of safety is to be 1.6, determine the smallest nominal diameter pipe that may be used to support the load.Three metal rods are firmly attached to the walls and the middle rigid plate. Rod AB is made from stainless steel and rods CD and EF are made from 2014-T6 aluminum. If a balanced load is applied to the rigid plate, determine what the stresses are in the rods. Follow the sign convention that tensile stress is positive and compressive stress is negative. The parameter values are listed in the table above the figure. A parameter value units 470 mm 400 mm 40 mm 30 mm 30 KN cc 080 BY NO SA 2021 Cathy Zupke L₁ L2 d₁ d₂ P 4₁ B C E The stress in AB σAB= The stress in CD and EF: OCD = EF= d₂ L₂ MPa D F MPa
- The hollow drill pipe for an oil well (sec figure) is 6,2 in. in outer diameter and 0.75 in. in thickness. Just above the bit, the compressive force in the pipe (due to the weight of the pipe) is 62 kips and the torque (due to drilling) is 185 kip-in. Determine the maximum tensile, compressive, and shear stresses in the drill pipe., Solve the preceding problem using the numerical data: /) = 90mm, h = 280 mm, d = 210 mm, q = 14 kN/m, and L = L2 m.A vertical pole consisting of a circular tube of outer diameter 5 in. and inner diameter 4.5 in. is loaded by a linearly varying distributed force with maximum intensity of q0, Find the maximum shear stress in the pole.