PROBLEM: A surveyor sets up a transit at point P which is located in the middle portion of a four-sided part of a land. He then takes and records the directions and distances, as given below, to the four vertices A, B, C, and D from point P. Find the area of the four-sided land by using the triangle method, in square meters. LINE BEARING DISTANCE PA N 41°30' W 410.51 m PB N 38°10' E 532.18 m PC S 70°20' E 450.75 m PD S 60°15' W 590.08 m

PROBLEM: A surveyor sets up a transit at point P which is located in the middle portion of a four-sided part of a land. He then takes and records the directions and distances, as given below, to the four vertices A, B, C, and D from point P. Find the area of the four-sided land by using the triangle method, in square meters. LINE BEARING DISTANCE PA N 41°30' W 410.51 m PB N 38°10' E 532.18 m PC S 70°20' E 450.75 m PD S 60°15' W 590.08 m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Point A B C D E F A Northing (ft) 2034.000 1652.332 1455.512 1293.631 1209.869 1332.100 2034.000 Easting (ft) 1829.593 1597.877 1642.700 1788.148 1562.188 1530.140 1829.593 Determine the Area in acres of the above traverse. (Show Work)
A parcel of land has been surveyed in the field and the lengths and bearings of the various sides are shown: a. Compute the error of closure for the traverse. b. Compute the precision of linear measurement. Determine the included area (using DPD method) within the traverse in acres. LINES AB BC CD DA BEARINGS N53' 27' E $ 66' 54'E $ 29'03' W N 52'00' W T DISTANCES (m) 59.82 70.38 76.62 95.75
2) A surveyor sets up a transit at P which is located in the middle portion of a four- sided tract of land and reads directions and measures distances, as given below, to the five corners. Find the area of the tract, in square meters. LINE BEARING DISTANCE N 41030' W Ν 38010, Ε S 70°20' E S 60°15' W AP 410.52 m ВР 532.18 m CP 450.75 m DP 590.08 m
Given the equations. Solve for y. х+у+z %3D 2, Зх — у — 2z %3D 4,5х — 2у + 3z 3D —7 O 1 O 3 О -2
Problem 11: Find the equation of the line with x – intercept 5 and y – intercept of - 3. С. 5х + Зу %3D 15 D. Зx + 5y %3D- 1 А. Зх — 5у %3 15 5x — Зу %3D 1 B.
X. Area by Triangle Point H is the middle portion of a four-sided tract of land and reads directions and measures distances. Compute the area of the given land in sqm. LINE BEARING N 43 35' W N 42 12' W S 32 20' W S 62 1¹ W A B C D DISTANCE 450.10 530.20 470.95 600.00
25. If the surveyor is at Point A, and recorded the location of Line AB to be 200 degrees 35 minutes in WCB. The surveyor then recorded the location of Line AC to be 280 degrees 15 minutes in WCB. The length of AB is 530.68 meters and Length of AC is 275.45 meters. What is the area of the Triangle ABC?
A line intercepts the x-axis at x = 3 and the y-axis at y = 8. What is the equation of the line? 8х — Зу%3D24 8х + 3у %3D 24 | А. Ов. -3x + 8y = 9 3x – 8 y = 9 C. D.
Q.4. Compute by DMDs the area in hectares within a closed-polygon traverse ABCDEFA by placing the X and Y axes through the most southerly and most westerly stations, respectively. Departures and latitudes (in meters) follow. AB: E dep. 30, N lat. = 40; BC: E dep. = 70, N lat. = 10; CD = E dep. = 30, S lat = 50; DE: W dep = 60, S lat. = 40; EF: W dep = 90, S lat = 30; FA: E dep. = 20, N lat = 70.
Situation 2] A surveyor was tasked to cut off a required area by a line through a given point. In the process of determining some required quantities there was a need to evaluate the resulting triangle BDP as shown. If the area of BDP is 630905.65 sqm, The length of line DP is? The length of dividing line BP is? The bearing of dividing line BP is? i. ii. iI. Trial Line 1419.63 m 12°17' 79928' B Dividing Line P
Y (Northig Calculate the area of closed traverse 。g 是 S E 喜蛋加出出湖%。。d 品是目器。 = さ曾 8 a & 8 胃8 88 品品品需品の

22.) Line MN, 251m long, was paced five times by the surveyor and recorded as follows: Trial No. Distance 1 121 2 122 3 120 4 124 5 122 Another line OP was paced four times again with the following results: Trial No. Distance 1 122 2 314 3 311 4 322 Determine the actual length of line OP.