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- The coefficient of friction between the inner pulley and the belt is 1/π. Find the maximum value of W that can be supported without rotating the compound pulley P or slipping the belt on the compound pulley P. Pulley B is frictionless. A 200 lb o A P B WA rope attached to a 500-lb block passes over a fric- tionless pulley and is wrapped for one full turn around a If the coefficient of frie- tion between the rope and the post is 0.25. determine fixed post as shown in Fig. The minimum force P that must be used to begin to raise the block. P WDetermine two force members first. Two blocks are each pin connected to a massless horizontal link. Determine the largest P before motion cocurs. Use 0.35 and 0.3 for the friction coefficients. 45° J c 4.5 kg 3 kg B 30°
- A traffic light of weight w hangs from two lightweight cables as shown. Each cable hangs at a 45° angle from the vertical. What is the tension in each cable? 45° 45° O w/2 w/1.41 2.82 w O 2 wThe forces are in static equilibrium. The 140 lb force is directed along the x-axis and the 300 lb force is directed along the negative z- axis. Determine the magnitude of the unknown force, R. Z X R Ox лог 140lb A (-50, 80, 160) lb By 300 lb уEstimate the power required for a boxer to jump rope.
- Determine two force members first. Two blocks are each pin connected to a massless horizontal link. Determine the largest P before motion cocurs. Use 0.35 and 0.3 for the friction coefficients. 4.5 kg 3 kg B 30°Diagram on right for Problems 12-15: Assume a frictionless pulley. T 125a N FN 351 kg 125 kg 351 kg H= 0.200 351a 45° 351(9.8) 125(9.8) 12. Calculate the force of the friction (FN) on the 351 kg m ass. EFy: N -351 (9.8)cos(45°) = 0 %3D cos(45) = sin(45°) = 0.707 FN = µN 13. Calculate the acceleration a of the 125 kg mass. EFx: 351a = 351(9.8)sin(45) - T -FN 125a = -125(9.8) + T 14. Calculate the tension (T) in the cable. (Hint: substitute a one of the above equations and solve for T) (round answer to three significant digits) a. 171 N b. 980 N c. 1255 N d. 1414 N 15. If the 351 kg mass moves for 3 seconds, what distance will it travel? (Use formula sat) S a. 4.86 m b. 6.82 m c. 9.72 m d. 14.1 mWe tie an 80 cm long rubber cord to the ceiling and attach a 50 g weight o its other end. The cord gets extended by 4.0 cm. We raise the weight to the ceiling and let it down. What is the force of the string, when the weight reaches its lowest point?
- A bridge of length 50.0 m and mass 8.10 x 104 kg is supported on a smooth pier at each end as shown in the figure below. A truck of mass 2.90 x 104 kg is located 15.0 m from one end. What are the forces on the bridge at the points of support? AM. A, В 15.0 m 50.0 m normal force at point A normal force at point B N Need Help? Read It Master ItThe guy wires AB and AC are attached to the top of the transmission tower. The tension in cable AB is 8.2 kN. Determine the required tension Tin cable AC such that the net effect of the two cables is a downward force at point A. Determine the magnitude R of this downward force. Assume a -41 m, b - 52 m, c-22 m, and d - 29 m. L B Answers: T- i KN R- i KN XXXIThe coefficient of friction between the 50 Ib weight and the 300 Ib weight is 0.5. The 300 Ib weight is free to roll, and the weight and friction for the pulley are negligible. When P=16lb, what is the acceleration of block B? B