Q3b. The stress-strain characteristic curves for materials A, B and C are shown below. Which one statement most accurately describes therelative toughness and ductility for materials A, B & C?Material AMaterial BMaterial CStrainSelect one:a. Material A has low toughness, Material B has high ductility and Material C has low toughness.b. Material A has high toughness, Material B has low ductility and Material C has low toughness.c. Material A has low ductility, Material B has low toughness and Material C has low toughness.d. Material A has high ductility, Material B has low toughness and Material C has high toughness.Stress

Given stress strain curve. The properties are At point A : High strength Low ductility Low…

Q3b. The stress-strain characteristic curves for materials A, B and C are shown below. Which one statement most accurately describes the relative toughness and ductility for materials A, B & C? Material A Material B Material C Strain Select one: O a. Material A has low toughness, Material B has high ductility and Material C has low toughness. O b. Material A has high toughness, Material B has low ductility and Material C has low toughness. O c. Material A has low ductility, Material B has low toughness and Material C has low toughness. O d. Material A has high ductility, Material B has low toughness and Material C has high toughness. Stress

Q3b. The stress-strain characteristic curves for materials A, B and C are shown below. Which one statement most accurately describes the relative toughness and ductility for materials A, B & C? Material A Material B Material C Strain Select one: O a. Material A has low toughness, Material B has high ductility and Material C has low toughness. O b. Material A has high toughness, Material B has low ductility and Material C has low toughness. O c. Material A has low ductility, Material B has low toughness and Material C has low toughness. O d. Material A has high ductility, Material B has low toughness and Material C has high toughness. Stress

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Mild steel 1 Young;s modulus 1219.5 Yield strain and stress (0.4101,500.08) Failure stress and strain :not able to find because the given data shows the experiment did not reach the failure point. if the material stress and strain does not reach a failure point ,what dose it means , does it means that the material is more stronger?
Consider the tensile stress-strain diagram below. If samples 1 and 2 are identical except that they were tested at different temperatures, which sample was tested at a lower temperature? Note: This question will be marked negatively so consider your answer carefully. A. Sample 1 B. Both were tested at the same temperature/ Alby is by die dieselfde temperatuur getoets C. Sample 2
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Sketch a representative stress-strain digrama for a ductile material showing the following on it (label the axis and provid units). 1- YIELD STRENGTH. 2- TENSILE STRENGTH. 3- FRACTURE POINT. 4- HARDENING PART. 5- SOFTENING PART. 6- A METHOD TO CALCULATE THE STIFFNESS. 7- A METHOD TO CALCULATE THE DUCTILITY.
For the stress-strain curves below, which statements are correct? Stress (MPa) 60 50 40 30 20 10 0 a. 0 b. O c. e. f. A 1 2 The mechanical behavior shown in C is that of an elastomer with low elastic modulus Polymer B and C have an elastic behavior whereas A has a plastic behavior While the deformation in polymer A is fully reversible until breakage, polymer B and C only display reversible deformation until 0.1X and 5x elongations respectively Od. The polymer with brittle nature is the one that possesses the highest elastic modulus The mechanical behavior shown in B is that of an elastomer with low elasticity The polymer with the necking behavior has the highest strength B с 3 4 5 6 7 8 Strain
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6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture)