Question 20 of 20 < A Water Balloon Battle. You are launching water balloons at a rival team using a large slingshot. The other team is set up on the opposite side of a flat-topped building that is 30.0 ft tall and 50.0 ft wide. Your reconnaissance team has reported that the opposition is set up 10.0 m from the wall of the building. Your balloon launcher is calibrated for launch speeds that can reach as high as 100 mph at angles between 0 and 85.0° from the horizontal. Since a direct shot is not possible (the opposing team is on the opposite side of the building), you plan to splash the other team by making a balloon explode on the ground near them. If your launcher is located 55.0 m from the building (opposite side as the opposing team), what should your launch velocity be ((a) magnitude and (b) direction) to land a balloon 5.0 meters beyond the opposing team with maximum impact (i.e. maximum vertical speed)? (a) Number (b) Number Units Units UNITS CHOICES: no units, degrees, s, kg, m, m/s, m/s^2, N, days 20

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter2: Kinematics
Section: Chapter Questions
Problem 19CQ: What is the last thing you should do when solving a problem? Explain.
icon
Related questions
icon
Concept explainers
Topic Video
Question
100%
Question 20 of 20 <
A Water Balloon Battle. You are launching water balloons at a rival team using a large slingshot. The other team is set up on the
opposite side of a flat-topped building that is 30.0 ft tall and 50.0 ft wide. Your reconnaissance team has reported that the opposition is
set up 10.0 m from the wall of the building. Your balloon launcher is calibrated for launch speeds that can reach as high as 100 mph at
angles between 0 and 85.0° from the horizontal. Since a direct shot is not possible (the opposing team is on the opposite side of the
building), you plan to splash the other team by making a balloon explode on the ground near them.
If your launcher is located 55.0 m from the building (opposite side as the opposing team), what should your launch velocity be ((a)
magnitude and (b) direction) to land a balloon 5.0 meters beyond the opposing team with maximum impact (i.e. maximum vertical
speed)?
(a) Number i
(b) Number i
Units
Units
UNITS CHOICES: no units, degrees, s, kg, m, m/s, m/s^2, N, days
20
Transcribed Image Text:Question 20 of 20 < A Water Balloon Battle. You are launching water balloons at a rival team using a large slingshot. The other team is set up on the opposite side of a flat-topped building that is 30.0 ft tall and 50.0 ft wide. Your reconnaissance team has reported that the opposition is set up 10.0 m from the wall of the building. Your balloon launcher is calibrated for launch speeds that can reach as high as 100 mph at angles between 0 and 85.0° from the horizontal. Since a direct shot is not possible (the opposing team is on the opposite side of the building), you plan to splash the other team by making a balloon explode on the ground near them. If your launcher is located 55.0 m from the building (opposite side as the opposing team), what should your launch velocity be ((a) magnitude and (b) direction) to land a balloon 5.0 meters beyond the opposing team with maximum impact (i.e. maximum vertical speed)? (a) Number i (b) Number i Units Units UNITS CHOICES: no units, degrees, s, kg, m, m/s, m/s^2, N, days 20
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Kinetic energy
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College