rences to access important values if needed for this question. The reduction of nitric oxide with hydrogen 2NO+2H₂ → N₂ + 2H₂O is second order in NO and first order in H₂. Complete the rate law for this reaction in the box below. Use the form k[A] [B]", where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear. Rate = In an experiment to determine the rate law, the rate constant was determined to be 1.74 x 10° Ms. Using this value for the rate constant, the rate of the reaction when [NO] = 0.451 M and [H₂] = 0.0805 M would be M/S.

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter13: Chemical Kinetics
Section: Chapter Questions
Problem 13.86QE
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rences to access important values if needed for this question.
The reduction of nitric oxide with hydrogen
2NO+2H₂ → N₂ + 2H₂O
is second order in NO and first order in H₂.
Complete the rate law for this reaction in the box below.
Use the form k[A] [B]", where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do
not appear.
Rate =
In an experiment to determine the rate law, the rate constant was determined to be 1.74 x 10° Ms. Using this value for
the rate constant, the rate of the reaction when [NO] = 0.451 M and [H₂] = 0.0805 M would be
M/S.
Transcribed Image Text:rences to access important values if needed for this question. The reduction of nitric oxide with hydrogen 2NO+2H₂ → N₂ + 2H₂O is second order in NO and first order in H₂. Complete the rate law for this reaction in the box below. Use the form k[A] [B]", where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear. Rate = In an experiment to determine the rate law, the rate constant was determined to be 1.74 x 10° Ms. Using this value for the rate constant, the rate of the reaction when [NO] = 0.451 M and [H₂] = 0.0805 M would be M/S.
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