Required information For equipment that has a first cost of $19,000, the estimated operating costs and year-end salvage values are as shown. Year Operating Cost, $ Salvage Value, $ -1,000 7,000 2 -1,200 5,000 3 -1,300 4,500 -2,000 3,000 5 -3,000 2,000 Determine the economic service life ESL, at i= 10% per year using factors. The economic service life ESL, is years with the AW = $-
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- New microelectronics testing equipment was purchased 2years ago by Mytesmall Industries at a cost of $600,000. Atthat time, it was expected to be used for 5 years and thentraded or sold for its salvage value of $75,000. Expandedbusiness in newly developed international markets is forcingthe decision to trade now for a new unit at a cost of$800,000. The current equipment could be retained, ifnecessary, for another 2 years, at which time it would have a$5000 estimated market value. The current unit is appraisedat $350,000 on the international market, and if it is used foranother 2 years, it will have M&O costs (exclusive ofoperator costs) of $125,000 per year. Determine the valuesof P, n, S, and AOC for this defender if a replacementanalysis were performed today. P = market value =$350,000AOC = $125,000 per yearn = 2 yearsS = $5,0005.24 For the cash flows below, use an annual worth comparison to determine which alternative is best at an interest rate of 1% per month. First cost, $ M&O costs, $/month Overhaul every 10 years, $ Salvage value, $ Life, years X -90,000 -400,000 -30,000 -20,000 - Y 7000 3 - 25,000 10 Z -900,000 -13,000 -80,000 200,000 8For equipment that has a first cost of $11,500, the estimated operating costs and year-end salvage values are as shown. Year 1 2345 Operating Cost, $ Salvage Value, $ -1,000 7,000 -1,200 5,000 -1,300 4,500 -2,000 3,000 -3,000 2,000 etermine the economic service life ESL, at /= 10% per year using factors. he economic service life ESL, is years with the AW= $-|
- A contractor has a 4-year concrete mixer whose first cost was $6,000, having 3 more years to live before being scrapped and sold at $801. Itcould now be sold for $11,922. It has an annual cost for operation and maintenance of $9,352. Its replacement is being proposed with a newmachine whose first cost will be $8,000 having a life of 9 years and salvage value $1,600. It has an operating cost of $800 per year andmaintenance cost of $320 per year. Ifthe interest is 20% cpd-a, what is the Annual Equivalent Cost of the Old Machine? 14,792Question 3 For the below ME alternatives, which machine should be selected based on the PW analysis. MARR=10% First cost, $ Annual cost, $/year Salvage value, $ Life, years Machine A Answer the below questions: A- PW for machine A= 23,979 8,679 4,000 Machine B 30000 6,000 5,000 Machine C 10000 4,000 1,000The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta-Start" does indeed work for every engine produced. First cost of equipment AOC per Year Salvage Value Estimated Life Pull System $-1,250,000 $-700,000 $105,000 8 years Push System $-2,350,000 $-500,000 $90,000 8 years Determine the salvage value for the push system that will make the company indifferent to the two systems. Also, MARR = 13% per year. The salvage value for the push system is determined to be $ in $1000 units.
- . Calculate the present worth of a machine which costs $105000 initially and has a 10 year life with a $20000 salvage value. The operating cost of the machine is expected to be $6000 in year 1(end_of_year) and $6600 in year 2, and amounts increasing by the 10% through its 10-year life. Use an interest rate of 12% per year. Please don't used excel I again says don't used excelAn industrial plant has hired a contractor to develop a solar farm nearby for the industrial plant's electricity consumption. During the 3-year construction period, the contractor will need to run a generator to power the construction. Cost analysis from previous projects indicates: Generator Brand Installed Cost Cost per Hour A $22M $500 B $23M $400 C $25M $250 D $30M $150 At the end of 3 years, the generator will have a salvage value equal to the cost of removing them. The generator will operate 6,000 hours per year. The lowest interest rate at which the contractor is willing to invest money is 7%. (The minimum required interest rate for invested money is called the minimum attractive rate of return, or MARR.) Select the alternative with the least present worth of cost. O Choice "C" with $29,872,900 O Choice "B" with $29,298,320 O Choice C with $28,936,450 O Choice "A" with $29,872,900Determine the ESL, at i = 15% per year for equipment that has a first cost of $8,000 and the estimated operating costs and year-end salvage values shown below Year Operation Cost Salvage Value $ per Year $ 1 -1000 2 -1200 3 -1300 4 -2100 1 year 2 years 3 years 4 years 6000 5000 3000 2000
- For th below two machines and based on AW analysis which machine we should select? MARR=10% Machine A Machine B 26612 12417 4135 Life, years 3 Answer the below question: B- the AW for machine B= First cost, $ Annual cost, $/year Salvage value, $ 140454 7170 infiniteThe Bureau of Public Highways is considering possible types of road surfacing with cost estimates per kilometer: Type B P650k First Cost Resurfacing period Resurfacing Cost Type A P500k 8 years P200k Average annual maintenance cost P15k The periodic resurfacing do not include the base of the subgrade. Compare these types by calculating the present worth for 24 year service, with no salvage value at the end of this time using interest rate of 10%. What if Capitalized Cost is used, which is better? 12 years P250k P20kQUESTION 3 For the below ME alternatives, which machine should be selected based on the AW analysis. MARR=10% First cost, $ Annual cost, $/year Salvage value, $ Life, years Machine A Answer the below questions : A- AW for machine A= 21,302 9,993 4,000 Machine B 30000 6,000 5,000 Machine C 10000 4,000 1,000