Researchers conducted an experiment to test the effects of alcohol. Errors were recorded in a test of visual and motor skills for a treatment group of 25 people who drank ethanol and another group of 25 people given a placebo. The errors for the treatment group have a standard deviation of 2.10, and the errors for the placebo group have a standard deviation of 0.82. Assume that the two populations are normally distributed. Use a 0.05 significance level to test the claim that both groups have the same amount of variation among the errors. OA. Ho: 0²=0² H₁:0² <0² OC. Ho: 0² #02/ H₁:0² = 0² Identify the test statistic. (Round to two decimal places as needed.) Use technology to identify the P-value. (Round to three decimal places as needed.) What is the conclusion for this hypothesis test? ….. OB. Ho: 0²=0²/2 H₁:0² *0² OD. H₂:0² = 0²/2 H₁:0² > 0² O A. Reject Ho. There is insufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors. OB. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors. OC. Reject Ho. There is sufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors. D. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors.
Researchers conducted an experiment to test the effects of alcohol. Errors were recorded in a test of visual and motor skills for a treatment group of 25 people who drank ethanol and another group of 25 people given a placebo. The errors for the treatment group have a standard deviation of 2.10, and the errors for the placebo group have a standard deviation of 0.82. Assume that the two populations are normally distributed. Use a 0.05 significance level to test the claim that both groups have the same amount of variation among the errors. OA. Ho: 0²=0² H₁:0² <0² OC. Ho: 0² #02/ H₁:0² = 0² Identify the test statistic. (Round to two decimal places as needed.) Use technology to identify the P-value. (Round to three decimal places as needed.) What is the conclusion for this hypothesis test? ….. OB. Ho: 0²=0²/2 H₁:0² *0² OD. H₂:0² = 0²/2 H₁:0² > 0² O A. Reject Ho. There is insufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors. OB. Fail to reject Ho. There is sufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors. OC. Reject Ho. There is sufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors. D. Fail to reject Ho. There is insufficient evidence to warrant rejection of the claim that both groups have the same amount of variation among the errors.
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter4: Equations Of Linear Functions
Section: Chapter Questions
Problem 8SGR
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