Rewrite the following for loop into a while loop: int s = 0; for (int i = 1; i <= 10; i++) { s += i;
Q: Write a while loop to print the product of the odd integers between 0 and 10, inclusive. Javascript
A: code snippet:
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A: Answer. Time Complexity = O(n^2) Space Complexity = O(1)
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A: (h) 334 (i) 5100
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A: As no programming language is mentioned, it is solved using basic C++
Q: Define a for loop to find the following output: 940+941 = 1881 313+314 = 627 104+105 = 209 34+35…
A: given: 940+941 = 1881 313+314 = 627 104+105 = 209 34+35 = 69 11+12 = 23 3+4 = 7
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A: Answer in step2
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A: Syntax: while Condition: # Loop-body Flowchart:
Q: Convert the following while loop to a for loop: int x %3; while (x < 50) { cout << "x is "<< x <<…
A: According to the asked question, the solution is given below with a proper explanation.
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A: In step 2, you will the python code.In step 3, you can see the sample output.
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Q: What is the output from the given for loop? for (int count = 10; count >= 1; count++) cout << count…
A: Output will be 10we can write count=count++; as two steps i.e.count=count;count=count+1;
Q: What is i after the following for loop? int y = 0; %3D for (int i = 0; i < 10; ++i) { %3D y += i; 0…
A: Given:-
Q: Write the following for loop as a while loop. for (int count = 1; count <= 10; count++) cout…
A: Syntax: while(Condition) { // Loop-body } Flowchart:
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A: The code is given below.
Q: 2- Question how many times does the following for loop execute? for (int k = 1; k <= 10; k--) a) 10…
A: Please see the below step for answer.
Q: Create a while loop that finds a product of all even numbers from 2 to 12.
A: Given : To create a while loop that finds a product of all even numbers from 2 to 12.
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A: We need to use nested for loops to solve this problem.
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A: Here have to determine about time complexity of given code.
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Q: loop to print the even numbers from 1 t
A: int number=100; for (int i=1; i<=number; i++) { //logic to check if the number is even…
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- int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;int n = 1; int k - 2; int r = n; if (k < n) { r - kint func(int a, int b) { return (a#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Number of digits int main() {int c=0;int i=3856; int l=i; while(l>0) {l=l/10; c++; } printf("%d",c); return 0; } Summation of digits int main() {int sum=0; int i=384; int l=i; while(l>0) { sum+=l%10; l=l/10;} printf("%d",sum); return 0; }void fact(int num) { int k,f=1; for (k=1;k<=num; k++) f=f*k; cout<< f; int main() { int arri[3]={3,2,1} ; for(int i=0;i<3;i++) fact(arri[i]); } 261 O 621 O 7 462a) FindMinIterative public int FindMin(int[] arr) { int x = arr[0]; for(int i = 1; i < arr.Length; i++) { if(arr[i]< x) x = arr[i]; } return x; } b) FindMinRecursive public int FindMin(int[] arr, int length) { if(length == 1) return arr[0]; return Math.Min(arr[length - 1], Find(arr, length - 1)); } What is the Big-O for this functions. Could you explain the recurisive more in details ?JAVA CODE PLEASE Functions With No Parameters and Return Values Quiz by CodeChum Admin Create a function named banner that prints “CodyChum” with a newline. In the main function, write a program that accepts an integer input which would serve as an inclusive stopping point of a loop iteration that starts at the value of 1. If the number that loops through the range is divisible by either 2 or 3, then call the banner function, otherwise just print the number. Input 1. One line containing an integer Output First line is the integer user input. Succeeding multiple lines containing an integer or “CodyChum” 10 1 CodyChum CodyChum CodyChum 5 CodyChum 7 CodyChum CodyChum CodyChumsum = 0; for (int i = 1; i< n; i = sum++ || 2*i)[Python Language] Using loops of any kind, lists, or Sets is not allowed. Sloan’s Book Collection Sloan loves reading books. She recently started reading an AI generated series called “Harry Trotter”. Sloan is collecting books from the series at her nearest bookstore. Since the series is AI generated, the publishers have produced an infinite collection of the books where each book is identified by a unique integer. The bookstore has exactly one copy of each book. Sloan wants to buy the books in the range [l,r], where l ≤ r. As an example, the range [−3,3] means that Sloan wants to buy the books − 3, − 2, − 1, 0, 1, 2, and 3. Pam also loves the series (or maybe annoying Sloan– who knows, really), and he manages to sneak into the bookstore very early to buy all of the books in the range [d,u], where d ≤ u. When Sloan later visits, sadly she will not find those books there anymore. For example, if Sloan tries to buy books [−2,3] and Pam has bought books [0,2], Sloan would only receive…Multiples(): Takes an int (n) as parameter and prints first 10 multiples n in a single line using for loop. Example: 5 5,10,15,20,25,30,35,40,45,50 class Main {public static void main(String[] args) {}}SEE MORE QUESTIONS