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rom Exercise 8.72 on page 349 in the textbook. Preliminary data analyses indicate that you can reasonably apply the z-interval procedure. Find a 90% confidence interval for the mean number of tongue flicks per 20 minutes for all juvenile common lizards. Assume a population standard deviation of 190.0. (Note: The sum of the data is 9047). Interpret your answer from part (a). Find a 99% confidence interval for ��. Why is the confidence interval you found in part ( c) longer than the one in part (a)? Draw a graph similar to the one shown in Figure 8.5 to display both confidence intervals. Which confidence interval yields more precise estimate of ?? Explain your answer. Exercise 8.72 & Figure 8.5 are attached

rom Exercise 8.72 on page 349 in the textbook. Preliminary data analyses indicate that you can reasonably apply the z-interval procedure. Find a 90% confidence interval for the mean number of tongue flicks per 20 minutes for all juvenile common lizards. Assume a population standard deviation of 190.0. (Note: The sum of the data is 9047). Interpret your answer from part (a). Find a 99% confidence interval for ��. Why is the confidence interval you found in part ( c) longer than the one in part (a)? Draw a graph similar to the one shown in Figure 8.5 to display both confidence intervals. Which confidence interval yields more precise estimate of ?? Explain your answer. Exercise 8.72 & Figure 8.5 are attached

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section: Chapter Questions
Problem 13PT
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  • from Exercise 8.72 on page 349 in the textbook. Preliminary data analyses indicate that you can reasonably apply the z-interval procedure.
    1. Find a 90% confidence interval for the mean number of tongue flicks per 20 minutes for all juvenile common lizards. Assume a population standard deviation of 190.0. (Note: The sum of the data is 9047).
    2. Interpret your answer from part (a).
    3. Find a 99% confidence interval for ��.
    4. Why is the confidence interval you found in part ( c) longer than the one in part (a)?
    5. Draw a graph similar to the one shown in Figure 8.5 to display both confidence intervals.
    6. Which confidence interval yields more precise estimate of ?? Explain your answer.

Exercise 8.72 & Figure 8.5 are attached

8.72 Smelling Out the Enemy. Snakes deposit chemical trails as they travel through their habitats. These trails are often detected and recognized by lizards, which are potential prey. The ability to recog- nize their predators via tongue flicks can often mean life or death for lizards. Scientists from the University of Antwerp were interested in quantifying the responses of juveniles of the common lizard (Lacerta vivipara) to natural predator cues to determine whether the behav- ior is learned or congenital. Seventeen juvenile common lizards were exposed to the chemical cues of the viper snake. Their responses, in number of tongue flicks per 20 minutes, are presented in the following table. [SOURCE: Van Damme et al., "Responses of Naïve Lizards to Predator Chemical Cues," Journal of Herpetology, Vol. 29(1), pp. 38-43] 425 510 629 236 654 200 276 501 811 332 424 674 676 694 710 662 633
Transcribed Image Text:8.72 Smelling Out the Enemy. Snakes deposit chemical trails as they travel through their habitats. These trails are often detected and recognized by lizards, which are potential prey. The ability to recog- nize their predators via tongue flicks can often mean life or death for lizards. Scientists from the University of Antwerp were interested in quantifying the responses of juveniles of the common lizard (Lacerta vivipara) to natural predator cues to determine whether the behav- ior is learned or congenital. Seventeen juvenile common lizards were exposed to the chemical cues of the viper snake. Their responses, in number of tongue flicks per 20 minutes, are presented in the following table. [SOURCE: Van Damme et al., "Responses of Naïve Lizards to Predator Chemical Cues," Journal of Herpetology, Vol. 29(1), pp. 38-43] 425 510 629 236 654 200 276 501 811 332 424 674 676 694 710 662 633
FIGURE 8.5 Margin of error, E s It Mean? of error for the X-Zα/2* σ √n E X E x+Za/2*
Transcribed Image Text:FIGURE 8.5 Margin of error, E s It Mean? of error for the X-Zα/2* σ √n E X E x+Za/2*
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