Safari File Edit View History Bookmarks Window Help )) 51% Sun 10:44 AM session.masteringchemistry.com Consider summer class... Inbox (13) - thesym1@g... Class Schedule Listing Schedule 111.009 & 111.... Ellucian Degree Works... Pearson's MyLab & Mas... ALEKS - Sofia Simmons... MasteringChemistry: H... II Review I Constants I Periodic Table Molarity (M) is defined as the number of moles of solute divided by the solution volume expressed in liters: The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab shelf: moles of solute molarity = Beaker Contents volume of solution (L) 200. mL of 1.50 M NaCl solution For example, 1 M HCl contains 1 mol of HCl dissolved in 1 L of solution. When a concentrated solution is diluted, the number of moles of solute stays constant; only the volume of the solution is changed. A dilution indicates an increase in solution volume and, therefore, the concentration of the solution must decrease. If you add more water to the HCl solution considered above, so that now the volume is 2 L, the number of moles remains the same but the volume is doubled. Hence the molarity of the solution is now 1 mol in a 2 L solution, that is, (1/2) M or 0.5 M. 100. mL of 3.00 M NaCl solution 3 150. mL of solution containing 22.0 g of NaCl 4 100. mL of solution containing 22.0 g of NaCl 300. mL of solution containing 0.450 mol NaCl Arrange the solutions in order of decreasing concentration. Rank from most concentrated to least concentrated. To rank items as equivalent, overlap them. • View Available Hint(s) The number of moles of solute before and after dilution can be calculated by multiplying molarity times volume. We can set up the following equations: Reset Help molarity x volume М, xИ%3 М х V moles of solute where M is the initial molarity (of the concentrated solution), Vi is the initial volume, Mf is the final molarity (of the diluted solution), and V is the final volume. 2 3 5 In the HCl solution example the initial molarity is 1 M, the initial volume is 1 L, the final volume is 2 L, and the molarity is 0.5 M. Thus the number of moles present in these solutions is Most concentrated Least concentrated M;V = M{ Vị =1 M× 1 L = 0.5 Mx 2 L = 1 mol 334Y03 átv FEB 23 MacBook Pro esc dele LO %24

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider summer class...
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<Homework 5
* Concentration
3 of 24
<>
II Review I Constants I Periodic Table
Molarity (M) is defined as the number of moles of solute
divided by the solution volume expressed in liters:
The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab shelf:
moles of solute
molarity =
Beaker
Contents
volume of solution (L)
200. mL of 1.50 M NaCl solution
For example, 1 M HCl contains 1 mol of HCl dissolved
in 1 L of solution. When a concentrated solution is diluted,
the number of moles of solute stays constant; only the
volume of the solution is changed. A dilution indicates an
increase in solution volume and, therefore, the
concentration of the solution must decrease. If you add
more water to the HCl solution considered above, so that
now the volume is 2 L, the number of moles remains the
same but the volume is doubled. Hence the molarity of the
solution is now 1 mol in a 2 L solution, that is, (1/2) M
or 0.5 M.
100. mL of 3.00 M NaCl solution
3
150. mL of solution containing 22.0 g of NaCl
4
100. mL of solution containing 22.0 g of NaCl
300. mL of solution containing 0.450 mol NaCl
Arrange the solutions in order of decreasing concentration.
Rank from most concentrated to least concentrated. To rank items as equivalent, overlap them.
• View Available Hint(s)
The number of moles of solute before and after dilution can
be calculated by multiplying molarity times volume. We can
set up the following equations:
Reset
Help
molarity x volume
М, xИ%3 М х V
moles of solute
where M is the initial molarity (of the concentrated
solution), Vi is the initial volume, Mf is the final molarity
(of the diluted solution), and V is the final volume.
2
3
5
In the HCl solution example the initial molarity is 1 M, the
initial volume is 1 L, the final volume is 2 L, and the
molarity is 0.5 M. Thus the number of moles present in
these solutions is
Most concentrated
Least concentrated
M;V = M{ Vị =1 M× 1 L = 0.5 Mx 2 L = 1 mol
334Y03
átv
FEB
23
MacBook Pro
esc
dele
LO
%24
Transcribed Image Text:Safari File Edit View History Bookmarks Window Help )) 51% Sun 10:44 AM session.masteringchemistry.com Consider summer class... Inbox (13) - thesym1@g... Class Schedule Listing Schedule 111.009 & 111.... Ellucian Degree Works... Pearson's MyLab & Mas... ALEKS - Sofia Simmons... MasteringChemistry: H... <Homework 5 * Concentration 3 of 24 <> II Review I Constants I Periodic Table Molarity (M) is defined as the number of moles of solute divided by the solution volume expressed in liters: The following five beakers, each containing a solution of sodium chloride (NaCl, also known as table salt), were found on a lab shelf: moles of solute molarity = Beaker Contents volume of solution (L) 200. mL of 1.50 M NaCl solution For example, 1 M HCl contains 1 mol of HCl dissolved in 1 L of solution. When a concentrated solution is diluted, the number of moles of solute stays constant; only the volume of the solution is changed. A dilution indicates an increase in solution volume and, therefore, the concentration of the solution must decrease. If you add more water to the HCl solution considered above, so that now the volume is 2 L, the number of moles remains the same but the volume is doubled. Hence the molarity of the solution is now 1 mol in a 2 L solution, that is, (1/2) M or 0.5 M. 100. mL of 3.00 M NaCl solution 3 150. mL of solution containing 22.0 g of NaCl 4 100. mL of solution containing 22.0 g of NaCl 300. mL of solution containing 0.450 mol NaCl Arrange the solutions in order of decreasing concentration. Rank from most concentrated to least concentrated. To rank items as equivalent, overlap them. • View Available Hint(s) The number of moles of solute before and after dilution can be calculated by multiplying molarity times volume. We can set up the following equations: Reset Help molarity x volume М, xИ%3 М х V moles of solute where M is the initial molarity (of the concentrated solution), Vi is the initial volume, Mf is the final molarity (of the diluted solution), and V is the final volume. 2 3 5 In the HCl solution example the initial molarity is 1 M, the initial volume is 1 L, the final volume is 2 L, and the molarity is 0.5 M. Thus the number of moles present in these solutions is Most concentrated Least concentrated M;V = M{ Vị =1 M× 1 L = 0.5 Mx 2 L = 1 mol 334Y03 átv FEB 23 MacBook Pro esc dele LO %24
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