served using the red LED at D1. You compared the charging time of the capacitor with the different resistor values series. You should have seen that D1 was lit for a significantly longer time with the higher value resistor. How is this st explained? fast. The 10KQ resistor is nearly twice as powerful as the 5k1Q resistor, allowing the capacitor to charge nearly twice The greater potential difference across the 10kQ resistor, compared to the 5k1Q resistor, allowed the capacitor to reach full voltage faster. The greater resistance of the 10kQ resistor allowed less current to flow, compared to the 5k1Q resistor. This caused the capacitor to charge more slowly. My LED did not light because it was never discharged, despite the instructions to do so.

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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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In STEP 2 you replaced the 5k12 resistor at R1 with a 10KQ resistor. The time required to charge the capacitor was
observed using the red LED at D1. You compared the charging time of the capacitor with the different resistor values
in series. You should have seen that D1 was lit for a significantly longer time with the higher value resistor. How is this
best explained?
O The 10KQ resistor is nearly twice as powerful as the 5k1Q resistor, allowing the capacitor to charge nearly twice as fast.
O The greater potential difference across the 10KQ resistor, compared to the 5k10 resistor, allowed the capacitor to reach full voltage faster.
O The greater resistance of the 10KQ resistor allowed less current to flow, compared to the 5k1Q resistor. This caused the capacitor to charge more
slowly.
O My LED did not light because it was never discharged, despite the instructions to do so.
Transcribed Image Text:In STEP 2 you replaced the 5k12 resistor at R1 with a 10KQ resistor. The time required to charge the capacitor was observed using the red LED at D1. You compared the charging time of the capacitor with the different resistor values in series. You should have seen that D1 was lit for a significantly longer time with the higher value resistor. How is this best explained? O The 10KQ resistor is nearly twice as powerful as the 5k1Q resistor, allowing the capacitor to charge nearly twice as fast. O The greater potential difference across the 10KQ resistor, compared to the 5k10 resistor, allowed the capacitor to reach full voltage faster. O The greater resistance of the 10KQ resistor allowed less current to flow, compared to the 5k1Q resistor. This caused the capacitor to charge more slowly. O My LED did not light because it was never discharged, despite the instructions to do so.
D1
Red
SW1
PSB
3.3 V
非
R1
C1
5.1 kQ
10 µF
+1
Transcribed Image Text:D1 Red SW1 PSB 3.3 V 非 R1 C1 5.1 kQ 10 µF +1
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