shafts transmitting power are subjected to
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The bolts in a rigid flanged coupling
connecting two shafts transmitting power are
subjected to
(a) shear force and bending moment
(b) axial force
(c) torsion
(d) torsion and bending moment
Step by step
Solved in 2 steps
- 1. A component in an aircraft flap actuator, shown in Figure 1, can be adequately modelled as a cylindrical bar subjected to a compressive axial force of 8 kN, a bending moment of 55 Nm and a torque of 30 Nm. It is to be manufactured of a 20 mm diameter solid bar of 7075-T6 aluminium alloy. FLAP ACTUATOR (a) (b) (c) (d) (e) POWER SCHEW JACK CARRIAGE -FAPERON BALL NUT FLAP NOSE ROLLER BEAM FITTING CARRIAGE ROLLER -COLLAPSIBLE DOOK Figure 1: Aircraft Flap Actuator At a critical point on the bar surface, determine the value of the, (1) compressive direct stress, (ii) (iii) tensile bending stress, and shear stress. Indicate on a representative element in 2-D cartesian coordinates the stresses calculated in (a). Determine the principal stresses and the maximum shear stress at the point. Sketch the Mohr's stress circle representing the stress system and clearly mark on it the principal stress values calculated in (c) above and the direction (angle) of the maximum principal stress (0₁) with…Torsional T is applied to the hollow axis (G=80 GPa). Ewha Womans University, the maximum shear strain is γmax = 640 × 10-6rad Igo, inside andThe outside diameters are 120mm and 150mm, respectively.a. What is the maximum axial strain?b. Maximum axial stress?c. What is the maximum torque (T) meeting the above conditions?Design a rigid flange coupling to transmit a torque of 250N-m between two coaxial shafts. The shaft is made of alloy steel, flanges out of cast iron and bolts out of steel. Four bolts are used to couple the flanges. The shafts are keyed to the flange hub. The permissible stresses are given below: Shear stress on shaft =100MPa Bearing or crushing stress on shaft =250MPa Shear stress on keys =100MPa Bearing stress on keys = 250MPa Shearing stress on cast iron = 200Mpa Shear stress on bolts =100MPa Torque = 257N-m
- A concentric shaft AB made of hollow bronze (OD = 100 mm, ID = 80 mm, G = 41 GPa) and solid steel (D = 80 mm, G = 80 GPa) is attached by a flanged bolt coupling at B to a solid aluminum shaft BC (D=90 mm, G = 28 GPa) which is then attached to a hollow brass shaft CD (OD = 100 mm, ID = 80 mm, G = 40 GPa). The whole shaft is fixed at ends A and D. The bolt coupling has a mismatch of 0.5 degree. Torque T is applied at C while a torque of 0.3T is being removed at B at the right flange plate. The bolt coupling has a bolt circle diameter of 120 mm and uses 15 bolts in which 3/5 are 50-mm in diameter and 2/5 are 25 mm in diameter. Determine the maximum permissible torque T that can be applied given the following allowable shear stresses: Thronze = 70 MPa, Usteel = 110 MPa, Taluminum = 60 MPa, Thrass = 55 Mpa, and Tbolts = 75 MP. A LAB = 2 m B ✈0.3T LBC = 1.5 m C T LCD = 1.5 m DA horizontal shaft AD supported in bearings at A and B and carrying pulleys at C and D is totransmit 75 kW at 500 r.p.m. from drive pulley D to off-take pulley C, Calculate the diameter of shaft. The data given is : P1 = 2 P2 (both horizontal), Q1 = 2 Q2 (bothvertical), radius of pulley C = 220 mm, radius of pulley D = 160 mm, allowable shear stress = 45 MPa.[Ans. 100 mm] Given CD=350mm CA=100mm AB=150mm BD=100mmTwo short shafts having identical diameters of 35 mm and rotating at 1000 rpm are connected by a flange coupling having five bolts with a 100 mm bolt circle. The design shearing stress of the bolt is 12 MPa and design compressive stress of the flange is 15 MPa. a. What is the power in kW transmitted by the short shaft? b. What is the torque transmitted by the shaft in lb-in? c. What diameter in mm of bolt should be used? d. How thick should the flange be in mm?
- In double hook joint, the angle of the driving and of the driven shaft with the intermediate shaft is 30°. The max ratio of the driven shaft to driving shaft angular velocities is (a) 3/4 (b) 4/3 (c) 1/2 (d) 1/4The shaft, is driven by pulley B from an electric motor. Another belt drivefrom pulley A is running a compressor. The belt tensions for pulley A are 1500 N and 600 N. The ratioof belt tensions for pulley B is 3.5. The diameter of pulley A is 150 mm and the diameter of pulley B is 480 mm. The allowable tensilestress for the shaft material is 170 MPa and the allowable shear stress is 85 MPa. Taking torsion andbending factors as 1.25 and 1.75 respectively, find the shaft diameter.Also find out the dimensions for a hollow shaft with outside diameter limited to 30 mm. Compare theweights of the two shafts. [Ans. 30 mm ; 24 mm ; 1.82 Given Length CD=350mm Length AB=150mm Length BD=100mm The total length is CD =350A crank loaded by a force F 1300 N that causes twisting and bending of a 20 mm -in-diameter shaft. (a) Draw separate free-body diagrams of the shaft AB and the arm BC, and compute the values of all forces, moments, and torques that act. Label the directions of the coordinate axes on these diagrams. BC and indicate where these act. (b) Locate a stress element on the top surface of the shaft at A, and calculate all the stress components that act upon this element. (c) Determine the maximum normal and shear stresses at A.
- Design a rigid flange coupling to transmit a torque of 257N-m between two coaxial shafts. The shaft is made of alloy steel, flanges out of cast iron and bolts out of steel. Four bolts are used to couple the flanges. The shafts are keyed to the flange hub. The permissible stresses are given below: Shear stress on shaft =100MPa Bearing or crushing stress on shaft =250MPa Shear stress on keys =100MPa Bearing stress on keys = 250MPa Shearing stress on cast iron = 200Mpa Shear stress on bolts =100MPa Answer in Word please- A flat spiral steel spring is to give a maximum torque of 1500 N-mm for a maximum stress of 1000 MPa. • Find the thickness and length of the spring to give three complete turns of motion, when the stress . decreases from 1000 to zero. The width of the spring strip is 12 mm. The Young's modulus for the material of the strip is 200 kN/mm2.Two sections of steel drill pipe, joined by bolted flange plates at Ä are being tested to assess the adequacy of both the pipes. In the test, the pipe structure is fixed at A, a concentrated torque of 500 kN - m is applied at x = 0.5 m, and uniformly distributed torque intensity t1= 250 kN m/m is applied on pipe BC. Both pipes have the same inner diameter = 200 mm. Pipe AB has thickness tAB=15 mm, while pipe BC has thickness TBC= 12 mm. Find the maximum shear stress and maximum twist of the pipe and their locations along the pipe. Assume G = 75 GPa.