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- Give two advantages of a stack-based IF as an example. Give an example of a drawback.I have discussed briefly in class how a stack can be used to evaluate normal mathematical expression (by normal, I mean infix notation expression). I proposed doing it in two phases: Converting an infix to a postfix expression. Evaluating the postfix expression. Both algorithms where discussed in class, and it was explained that a stack data structure is needed to implement both algorithm phases. When dealing with postfix expression, two edge issues need to be handled: First, regarding negative numbers, it is important to distinguish the unary negative sign (such us -5) from the binary subtraction operation (such us 3-5) in your implementation code. For example, one way is to substitute the unary symbol from - (minus) to another symbol (such as ~), and consider it as part of the operand, not an operation: for example ~5 is the (minus five operand). That substitution should be only implemented internally, but the program should still accept it. Of course, you can come up with…Show that a permutation may only be created by a stack (as in the previous question) if it does not contain the banned triple (a, b, c) such that a b c with c first, a second, and b third (potentially with other intervening integers between c and a and between a and b).
- Produce the PDA that decides the following language. You do not need to show the full 6-tuple, but you should show your stack alphabet (T) {a"b" :n < m < 2n}. Consider the infix expression 15 + 2 – 10 / 2 ∗ 2 and convert this into postfix expression using stack. Next Token Action Effect on operatorStack Effect on postfix 15 + 2 - 10 / 2 * 2Please name two advantages of employing a stack-based IF as an illustration. Provide an illustration of one of the drawbacks.
- Examine the performance of the stack under situations in which it is allowed to act naturally.You are allowed to operate on a stack WORK and a temporary stack TEMP (ifneeded) supporting their ADT operations of PUSH (S,X), POP (S, X) andEMPTYSTACK (S) only, where X represents an element/variable to be pushed in orpopped out of the stack and S represents a stack. You are also permitted to use onevariable if needed to carry out the operations.i) Given n distinct random numbers that are to be pushed into WORK, how canyou find the minimum element that was pushed into it? You are permitted to use alone variable.ii) Given n distinct random numbers that are to be pushed into WORK, how canyou find the maximum element that was pushed into it, all the while ensuring thatthe elements stored in WORK are in their descending order with the maximumelement beginning at the bottom of stack? You are permitted to use a lone variableand a temporary stack TEMP.iii) Given an array A[1: n] of distinct random numbers how can you obtain thesorted list in the array, making use of stacks alone?If a linked stack is implemented as a doubly linked list, provide a process to flip the stack such that the top and bottom places are now the bottom and top, respectively.A connected stack S and its reversed counterpart Srev, for instance, are displayed as follows:
- Whereas the unbounded stack has no such limits, could you perhaps elaborate on how this works?Solve the code much needed. Given a stack, a function is_consecutive takes a stack as a parameter and thatreturns whether or not the stack contains a sequence of consecutive integersstarting from the bottom of the stack (returning true if it does, returningfalse if it does not). For example:bottom [3, 4, 5, 6, 7] topThen the call of is_consecutive(s) should return true.bottom [3, 4, 6, 7] topThen the call of is_consecutive(s) should return false.bottom [3, 2, 1] topThe function should return false due to reverse order. Note: There are 2 solutions:first_is_consecutive: it uses a single stack as auxiliary storagesecond_is_consecutive: it uses a single queue as auxiliary storage"""import collections def first_is_consecutive(stack): storage_stack = [] for i in range(len(stack)): first_value = stack.pop() if len(stack) == 0: # Case odd number of values in stack return True second_value = stack.pop() if first_value - second_value != 1: # Not…You may operate on a stack WORK and a temporary stack TEMP (if necessary) to enable its ADT operations of PUSH (S,X), POP (S, X), and EMPTYSTACK (S), where X represents an element/variable to be pushed into or popped out of the stack and S represents a stack. You may also utilise one variable to carry out the procedures if necessary. I Given n different random integers to be pushed into WORK, how can you determine the maximum element pushed into it while ensuring that the items placed in WORK are in decreasing order, with the maximum element beginning at the bottom of the stack? You may utilise a single variable and the temporary stack TEMP. ii) Given an array A[1: n] of different random numbers, how can you extract the array's sorted list using only stacks?