All measurements shown in mm. The connected plates are 10mm. Apply NSCP Specs for welded connections. Fy =420MPa, Fu = 580MPa. L2is the length of the transverse weld. Note: L1 = 500mm, L3 = 500 & width = 300mm.1. Determine the maximum weld thickness that can be used.2. Determine the effective weld length of each weld if the actual welds used in the connection is 4mm. L2 =300mm.3. If the plates used are 10 mm, determine the tension yielding and rupture capacity. Consider θ = 0°, L2 = 0 and LRFD NSCP 2015.4. If the welds used are 8 mm, determine the weld capacity. Consider θ = 0°, L2 = 300mm. Weld strength, Fw = 485MPa. LRFD.5. If the welds used are 8 mm, determine the weld capacity. Consider θ = 30°, L2 = 0mm. LRFD. Situation 5:All measurements shown in mm. The connected plates are 10mm. Apply NSCP Specs for welded connections. Fy =420MPa, F = 580MPa. L₂is the length of the transverse weld. Note: L1 = 500mm, L3 = 500 & width = 300mm.1. Determine the maximum weld thickness that can be used.2. Determine the effective weld length of each weld if the actual welds used in the connection is 4mm. L₂ =300mm.3. If the plates used are 10 mm, determine the tension yielding and rupture capacity. Consider 9=0°, L₂ = 0 andLRFD NSCP 2015.4. If the welds used are 8 mm, determine the weld capacity. Consider = 0°, L₂ = 300mm. Weld strength, Fw=485MPa. LRFD.5. If the welds used are 8 mm, determine the weld capacity. Consider = 30°, L₂ = 0mm. LRFD.L1L3deg

Solution based on NSCP Specs for Welded ConnectionsGiven Information:Plate thickness (t) = 10…

Situation 5: All measurements shown in mm. The connected plates are 10mm. Apply NSCP Specs for welded connections. Fy = 420MPa, F = 580MPa. L₂is the length of the transverse weld. Note: L1 = 500mm, L3 = 500 & width = 300mm. 1. Determine the maximum weld thickness that can be used. 2. Determine the effective weld length of each weld if the actual welds used in the connection is 4mm. L₂ = 300mm. 3. If the plates used are 10 mm, determine the tension yielding and rupture capacity. Consider 9=0°, L₂ = 0 and LRFD NSCP 2015. 4. If the welds used are 8 mm, determine the weld capacity. Consider = 0°, L₂ = 300mm. Weld strength, Fw= 485MPa. LRFD. 5. If the welds used are 8 mm, determine the weld capacity. Consider = 30°, L₂ = 0mm. LRFD. L1 L3 deg

Situation 5: All measurements shown in mm. The connected plates are 10mm. Apply NSCP Specs for welded connections. Fy = 420MPa, F = 580MPa. L₂is the length of the transverse weld. Note: L1 = 500mm, L3 = 500 & width = 300mm. 1. Determine the maximum weld thickness that can be used. 2. Determine the effective weld length of each weld if the actual welds used in the connection is 4mm. L₂ = 300mm. 3. If the plates used are 10 mm, determine the tension yielding and rupture capacity. Consider 9=0°, L₂ = 0 and LRFD NSCP 2015. 4. If the welds used are 8 mm, determine the weld capacity. Consider = 0°, L₂ = 300mm. Weld strength, Fw= 485MPa. LRFD. 5. If the welds used are 8 mm, determine the weld capacity. Consider = 30°, L₂ = 0mm. LRFD. L1 L3 deg

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter8: Eccentric Connections

Section: Chapter Questions

Problem 8.4.13P

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