STEP BY STEP Exaplanation would be appreciated so I can understand for upcomming exam. In humans, the COL1A1 locus codes for a collagen protein found in bone.  A recessive COLA1 allele believed to reduce bone density and increase risk of fractures differs from the wild type allele by the presence a GT in the first intron of the gene. This mutation can be easily screened by PCR, using COL1A1-specific primers followed restriction enzyme digest of the product with MscI. The normal allele is denoted as G and the recessive allele as T.  A recent study of 894 women found that 570 were GG, 291 were GT and 33 were TT.  (Assume for this exercise that these values reflect both male and female values for the sampled population. What are the frequencies of each allele? What are the frequencies of each genotype? c. Is this locus in Hardy-Weinberg equilibrium? Use the table below to evaluate the significance of any deviation from H-W expectations.

Case Studies In Health Information Management
3rd Edition
ISBN:9781337676908
Author:SCHNERING
Publisher:SCHNERING
Chapter6: Leadership
Section: Chapter Questions
Problem 6.41.1C
icon
Related questions
Question

STEP BY STEP Exaplanation would be appreciated so I can understand for upcomming exam.

In humans, the COL1A1 locus codes for a collagen protein found in bone.  A recessive COLA1 allele believed to reduce bone density and increase risk of fractures differs from the wild type allele by the presence a GT in the first intron of the gene. This mutation can be easily screened by PCR, using COL1A1-specific primers followed restriction enzyme digest of the product with MscI. The normal allele is denoted as G and the recessive allele as T.  A recent study of 894 women found that 570 were GG, 291 were GT and 33 were TT.  (Assume for this exercise that these values reflect both male and female values for the sampled population.

  1. What are the frequencies of each allele?
  2. What are the frequencies of each genotype?

c. Is this locus in Hardy-Weinberg equilibrium? Use the table below to evaluate the significance of any deviation from H-W expectations.

df
P= 0.05
P = 0.01
P=0.001
1
3.84
6.64
10.83
5.99
7.82
9.21
13.82
3
11.35
16.27
4
9.49
13.28
18.47
5
11.07
15.09
20.52
12.59
16.81
22.46
Transcribed Image Text:df P= 0.05 P = 0.01 P=0.001 1 3.84 6.64 10.83 5.99 7.82 9.21 13.82 3 11.35 16.27 4 9.49 13.28 18.47 5 11.07 15.09 20.52 12.59 16.81 22.46
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 2 images

Blurred answer
Knowledge Booster
Genomic studies
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Case Studies In Health Information Management
Case Studies In Health Information Management
Biology
ISBN:
9781337676908
Author:
SCHNERING
Publisher:
Cengage
Principles Of Pharmacology Med Assist
Principles Of Pharmacology Med Assist
Biology
ISBN:
9781337512442
Author:
RICE
Publisher:
Cengage
Essentials Health Info Management Principles/Prac…
Essentials Health Info Management Principles/Prac…
Health & Nutrition
ISBN:
9780357191651
Author:
Bowie
Publisher:
Cengage
Understanding Health Insurance: A Guide to Billin…
Understanding Health Insurance: A Guide to Billin…
Health & Nutrition
ISBN:
9781337679480
Author:
GREEN
Publisher:
Cengage
Curren'S Math For Meds: Dosages & Sol
Curren'S Math For Meds: Dosages & Sol
Nursing
ISBN:
9781305143531
Author:
CURREN
Publisher:
Cengage