Suppose that P(X > 3) = 0.3, then O None of these a=0.44; b=0.26 a=0.42; b=0.29 a=0.34; b=0.26
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- (26) Let X b(8,- Var-x) and distribution function.Jump to... Suppose Y follows a Chi-square distribution with 35 degrees of freedom. Which of the following Microsoft Excel commands can be used to calculate P( 20 < Y < 30 ). CHISQ.DIST ( 20; 35; TRUE )- CHISQ.DIST ( 30; 35; TRUE ) O= CHISQ,DIST.RT ( 30 ; 35 )- CHISQ.DIST.RT( 20; 35) O=CHISQ.DIST ( 20; 35 )- CHISQ.DIST ( 30; 35 ) O= CHISQ.DIST.RT ( 20; 35)- CHISQ.DIST.RT(30; 35) O= CHISQ.DIST.RT ( 20; 35; FALSE) - CHISQ.DIST.RT( 30; 35; FALSE) Previous page Next page Return to: ASSESSMENTSWith reference to Example 4, verify that the values ofthe distribution function are given by F(x) = x2 + 5x50 for x = 1, 2, 3, 4, and 5.
- Show that the t-distribution with r = 1 degree of freedom and the Cauchydistribution are the same.If the distribution function f(q) for some physical property q is even, it follows that q = 0. Does it also follow that the most probable value q* = 0?Suppose insurance loss X follows a Pareto distribution with mean 200 and variance 60,000. (a) Find α, and θ. (b) Find eX(100). (c) Find VaR0.95(X). (c) Find TVaR0.95(X)
- Suppose X has a continuous uniform distribution over the interval [-2, 2]. Determine (a) Mean (b)variance, and (c) standard deviation of XFind the mean and variance for the probability distribution given by f(x)= 2x k(k+1)* -,x=1,2,3,...kSuppose the current in a diode is assumed to follow a normal distributionwith mean of 9mA and variance of 9mA. What is the probability that ameasurement will exceed 12mA ?. Given that ߶(1) = 0.8413, where ߶(. )represents the distribution function of N(0,1).
- The random variable X has a distribution function:F(x) = 0 ; x < 3 = 1/c(x2 - 3x) ; 3 <= x <=6 = 1 ; x > 6 Count the value of constant "c" Count the P(X > 4) and P(5 <= X <= 6) Count the median of X Thanks for help!The frog wants to send a gift to the princess. He needs to jump a total distance of 10 meters to reach her. Suppose that each time, the frog independently generates a random variate from the normal distribution N(1,1). If the generated variate is below zero, the frog will jump away from the princess. If the generated variate is above zero, the frog will jump towards the princess. The distance that the frog covers in each jump is the absolute value of the variate. Calculate the probability that after two jumps, the frog has still not reached the princess.(2). Let st have the distribution of X ~N(4,16). (a). P(x >xo) = 0.05, (b). Fmd the number Xo smce P(X>-x) - 0.95