Suppose that the position of one particle at time t is given by x1 = 5 sin(t),    y1 = 2 cos(t),    0 ≤ t ≤ 2? and the position of a second particle is given by x2 = −5 + cos(t),    y2 = 1 + sin(t),    0 ≤ t ≤ 2?.   1) find the collision points. (Enter your answers as a comma-separated list of ordered pairs. If an answer does not exist, enter DNE.)

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A: formula for average value is  favga=1b-a∫abf(x)dx∫1xdx=lnx

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A: Topic = Integration

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A: Please see the below picture for detailed solution.

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A: Solve the following

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A: Explained below

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