T.J. wants to estimate the percentage of college students who have taken out student loans. He surveys 400 students and finds that 190 have taken out student loans. Find the confidence interval for the population proportion with a 95% confidence level.

Q: Use the confidence interval to find the margin of error and the sample mean. (0.558,0.740)

A: Given: confidence interval ( 0.558 , 0.74 ) Need to find sample mean(x̄) and margin of error(ME) .

Q: Kim wants to determine a 99 percent confidence interval for the true proportion of high school…

A: From the given information, Margin error (E) = 0.03 Assume sample proportion = 0.5   The objective…

Q: Dylan wants to determine a 99 percent confidence interval for the true proportion of high school…

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Q: Find the 95% confidence interval for the mean difference of the tests, and explain it.

A: Test - 1 (X) Test-2 (Y) (x-xbar) (x-xbar)^2 (y-ybar) (y-ybar)^2 1.2 1.4 -0.31111 0.09679 -0.24444…

Q: Decreasing the sample size, while holding the confidence level the same, will do what to the length…

A: Introduction: Confidence interval is the interval estimate of the population parameter. It is the…

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

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Q: A television station surveys 200 customers and finds that 23% of customers watch the evening news.…

A: Given data n=200 p=23% confidence level=99%

Q: Use the confidence interval to find the margin of error and the sample mean. (.228, 0.390)

A: We know that the Margin of error = (upper_limit - lower_imit )/2 and Sample mean = (upper limit +…

Q: The County Development Agency does a survey of all the mobile home manufacturers in Clarion County…

A: X̄ = $13,550, σ = $2,000, n = 25,

Q: Using the 99% level of confidence, what is the confidence interval for proportion of students…

A: Let X be the random variable such number of students attending home football games. X = 750 N: Total…

Q: Explain the Other Types of Confidence Intervals.

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Q: Suppose that you will be taking a random sample from a population and that you intend to find a 95%…

A: Solution: The confidence interval for the population mean is calculated by using the following…

Q: A television sports commentator wants to estimate the proportion of citizens who​ "follow…

A: Solution: From the given information, confidence level is 0.96 and E=0.02.

Q: The confidence interval was (22, 26) What was the point estimate? What was the margin of error?

A: Given confidence interval was (22, 26)

Q: Find the confidence level and α for a. an 85% confidence interval. b. a 95% confidence interval.

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Q: Professor Smith loves dark chocolate, and she would like to find out the proportion of the…

A: Given Information: Sample size (n) = 850 Out of which x = 600 people chose dark chocolate.…

Q: A quality controller wants to estimate the proportion of high quaity goods out of a batch of…

A:

Q: The County Development Agency does a survey of all the mobile home manufacturers in Clarion County…

A:

Q: The 90% confidence interval for the population proportion p is (,) The 95% confidence interval for…

A: here n = 634 p^ = proportion of males gone to dentist pin past year = 390634 = 0.6151 z-critical for…

Q: the sample proportion of females is  x=118  n=164 P = .720  #1 Make a 95% confidence interval for…

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Q: In the Laboratory Activity, we used 90% confidence interval instead of 100%, why is this so? Why not…

A: Confidence Interval A confidence interval (CI) is a set of numbers that assess the validity of the…

Q: The confidence interval was (77, 83) What was the point estimate? What was the margin of error?

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Q: In a survey, the planning value for the population proportion is .25. How large a sample should be…

A: We have to find sample size..

Q: To determine the proportion of Americans who support affirmative action policies for minorities and…

A: The objective is to define the sample size for estimating the true proportion of Americans, who…

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

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Q: A researcher wants to do a study to see what the proportion of vaccinated people is in a certain…

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Q: Cora wants to determine a 90 percent confidence interval for the true proportion of high school…

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Q: f n=300 and ˆpp^ (p-hat) =0.18, find the margin of error at a 99% confidence level Give your answer…

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Q: Of the 1,000 people, 550 people used company s's smartphone and 460 people used company a's…

A: Given: n= 1000 ,x= 550.0 At 95.0 % confidence level , z score= 1.96 Need to find confidence…

Q: Is 12 minutes the margin of error for this 95% confidence interval v [Select ]

A: The 95% confidence interval for the average arrival time before departure for all air travellers is…

Q: Use the confidence interval to find the margin of error and the sample mean. (1.59,1.89)

A: Given data,Lower limit=1.59Upper limit=1.89Margin of error=?

Q: Explain the three properties of confidence intervals.

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Q: Find the confidence level and a for an 88% confidence interval.

A: Here use confidence level and significance level as alternative of each other

Q: Determine the margin of error for the confidence interval for the proportion: 0.518 <p<0.774 The…

A: We have to find margin of error

Q: Use the confidence interval to find the margin of error and the sample mean.   (.364,0.500)

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Q: The confidence interval was (64, 76) What was the point estimate? What was the margin of error?

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Q: Use the confidence interval to find the margin of error and the sample mean. (0.456,0.620)

A: The confidence interval is given by (0.456, 0.620) Let M denote the sample mean, And E denote the…

Q: People were surveyed worldwide, being asked the question "How important is acquiring wealth to you?…

A: The sample proportion is calculated using the formula:

Q: Michelle, a student studying music, randomly sampled fellow music majors and asked whether they…

A: Given information- Confidence interval = (0.09, 0.26) We have to find margin of error. We know that-…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given data, n=195 x=126 p=x/n=126/195=0.646   z-value at 95% confidence is Zc=1.96

Q: previous election, the confidence interval for the proportion of likely voters who would vote for…

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Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: What is the t-value for a 90% confidence interval given that the sample size is 26? Write the exact…

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Q: Astudent polls his school to see if students in the school district are for or against the new…

A: We have given that  Sample size N=600 and favorable cases X=480 Sample proportion p^=X/N

Q: Find the confidence level and α for a. a 90% confidence interval. b. a 99% confidence interval.

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Q: Aston’s Career Service wants to find out what proportion of Aston’s students work in a part-time…

A: From the given information, Population proportion = p = 60% = 0.60 Margin of error = E = 4% = 0.04…

Q: Find the margin of error for the given confidence level and values of x and n. x = 111, n = 194,…

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Q: Melissa wants to estimate the proportion of adults in the U.S. who own a gun. To do so, she surveys…

A: Given information: Sample size of adults is 45, that is, n = 45. Number of adults who own a gun is…

Q: Solve for the sample size with the assumption that the confidence coefficient is 95% and second, the…

A: Sample size estimation is integral part of inferential statistic.