That's enough for you! def first_preceded_by_smaller(items, k=1): Find and return the 0irst element of the given list of items that is preceded by at least k smaller elements in the list. These required k smaller elements can be positioned anywhere before the current element, not necessarily consecutively immediately before that element. If no element satisfying this requirement exists in the list, this function should return None. Since the only operation performed for the individual items is their order comparison, and especially no arithmetic occurs at any point during execution, this function should work for lists of any types of elements, as long as those elements are pairwise comparable with each other. items k Expected result [4, 4, 5, 6] 2 5 [42, 99, 16, 55, 7, 32, 17, 18, 73] 3 18 [42, 99, 16, 55, 7, 32, 17, 18, 73] 8 None ['bob', 'carol', 'tina', 'alex', 'jack', 'emmy', 'tammy', 'sam', 'ted'] 4 'tammy' [9, 8, 7, 6, 5, 4, 3, 2, 1, 10] 1 10 [42, 99, 17, 3, 12] 2 No

That's enough for you! def first_preceded_by_smaller(items, k=1): Find and return the 0irst element of the given list of items that is preceded by at least k smaller elements in the list. These required k smaller elements can be positioned anywhere before the current element, not necessarily consecutively immediately before that element. If no element satisfying this requirement exists in the list, this function should return None. Since the only operation performed for the individual items is their order comparison, and especially no arithmetic occurs at any point during execution, this function should work for lists of any types of elements, as long as those elements are pairwise comparable with each other. items k Expected result [4, 4, 5, 6] 2 5 [42, 99, 16, 55, 7, 32, 17, 18, 73] 3 18 [42, 99, 16, 55, 7, 32, 17, 18, 73] 8 None ['bob', 'carol', 'tina', 'alex', 'jack', 'emmy', 'tammy', 'sam', 'ted'] 4 'tammy' [9, 8, 7, 6, 5, 4, 3, 2, 1, 10] 1 10 [42, 99, 17, 3, 12] 2 No

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter17: Linked Lists

Section: Chapter Questions

Problem 18PE

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That's enough for you! def first_preceded_by_smaller(items, k=1): Given a list of items, find and return the value of the first element for which at least k smaller elements precede that element in items. If no such element exists inside the list, this function should return None. The required k smaller items do not need to be consecutive immediate predecessors of the current item, but can be any k items positioned before the current element. items k Expected result [4, 4, 5, 6] 2 5 [42, 99, 16, 55, 7, 32, 17, 18, 73] 3 18 [42, 99, 16, 55, 7, 32, 17, 18, 73] 8 None ['bob', 'carol', 'tina', 'alex', 'jack', 'emmy', 'tammy', 'sam', 'ted'] 4 'tammy' [9, 8, 7, 6, 5, 4, 3, 2, 1, 10] 1 10 [42, 99, 17, 3, 12] 2 None
Recamán's sequence def recaman_item(n):Compute and return the n:th term of the Recamán's sequence. See the linked definition for this sequence on Wolfram Mathworld. Note how the definition for the current element in this sequence depends on whether some particular number can be found in the previously generated prefix of the sequence. To allow your function to execute in a sure and speedy fashion even for millions of elements, you should use a set to keep track of which elements are already part of the prefix of the sequence generated so far. This way you can generate each element in constant time, instead of having to iterate through the entire previously generated list the way some "Shlemiel" might approach this problem. n Expected result 1 1 8 12 13 23 57 87 395743 258330 The previous version of this problem, simply called recaman in the very first versions of this problem collection,…
Write a function that takes in n ADT Lists in an array. The function is going to be called Intersection, and it will return a new list with the elements common to all the n lists. Determine the time complexity
Count dominators def count_dominators(items): An element of items is said to be a dominator if every element to its right (not just the one element that is immediately to its right) is strictly smaller than it. By this definition, the last item of the list is automatically a dominator. This function should count how many elements in items are dominators, and return that count. For example, dominators of [42, 7, 12, 9, 13, 5] would be the elements 42, 13 and 5. Before starting to write code for this function, you should consult the parable of "Shlemiel the painter" and think how this seemingly silly tale from a simpler time relates to today's computational problems performed on lists, strings and other sequences. This problem will be the first of many that you will encounter during and after this course to illustrate the important principle of using only one loop to achieve in a tiny fraction of time the same end result that Shlemiel achieves with two nested loops. Your workload…
You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…
Max Absolute In List Function Lab Description Implement function max_abs_val(lst), which returns the maximum absolutevalue of the elements in list.For example, given a list lst: [-19, -3, 20, -1, 0, -25], the functionshould return 25. The name of the method should be max_abs_val and the method should take one parameter which is the list of values to test. Here is an example call to the function print(max_abs_val([-19, -3, 20, -1, 0, -25])) File Name maxabsinlst.py Score There are three tests each worth 2 points Note: You do not need any other code including the main method or any print statements. ONLY the max_abs_val method is required. Otherwise, the autograder will fail and be unable to grade your code. (I.e., do not include the above example in your code.) The above example should be used be test your code but deleted or comment out upon submission. PYTHON LAB
The function that will a single items to the list is Oextend (...) Oadd(...) Oappend(...) Olengthen(...)
The following function is designed to take in a nested list structure of unknown depth, where each element at every level is either an integer or a list. The function should return a copy of the nested list structure, but with all integer values increased by 1. Fill in the blanks in the function such that it works as intended. def deep_add(collection): if isinstance (collection, int): #Checks if collection is an int return elif collection return else: == []: return [deep_add(collection [0])] +
The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
True/False Select true or false for the statements below. Explain your answers if you like to receive partial credit. 3) Which of the following is true about the insertBeforeCurrent function for a CircularLinked List (CLL) like you did in programming exercise 1?a. If the CLL is empty, you need to create the new node, set it to current, andhave its next pointer refer to itselfb. The worst case performance of the function is O(n)c. If you insert a new element with the same data value as the current node, theperformance improves to O(log n)
Domino cycledef domino_cycle(tiles):A single domino tile is represented as a two-tuple of its pip values, such as (2,5) or (6,6). This function should determine whether the given list of tiles forms a cycle so that each tile in the list ends with the exact same pip value that its successor tile starts with, the successor of the last tile being the first tile of the list since this is supposed to be a cycle instead of a chain. Return True if the given list of domino tiles form such a cycle, and False otherwise. tiles Expected result [(3, 5), (5, 2), (2, 3)] True [(4, 4)] True [] True [(2, 6)] False [(5, 2), (2, 3), (4, 5)] False [(4, 3), (3, 1)] False
Write a Python Code for the given function and conditions: Given function: def insert(self, newElement) Pre-condition: None. Post-condition: This method inserts newElement at the tail of the list. If an element with the same key as newElement already exists in the list, then it concludes the key already exists and does not insert the key.

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items	k	Expected result
[4, 4, 5, 6]	2	5
[42, 99, 16, 55, 7, 32, 17, 18, 73]	3	18
[42, 99, 16, 55, 7, 32, 17, 18, 73]	8	None
['bob', 'carol', 'tina', 'alex', 'jack', 'emmy', 'tammy', 'sam', 'ted']	4	'tammy'
[9, 8, 7, 6, 5, 4, 3, 2, 1, 10]	1	10
[42, 99, 17, 3, 12]	2	None