Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
The American Burn Association states 3. You heat up an aluminum sphere of radius r, 1.27254 cm to 100 °C. You cool a 20.0 g copper ring to 0.00000 °C. The inner radius of the copper ring is r, 1.27000 cm. You then place the sphere on top of the ring and they are allowed to reach thermal equilibrium. Assume no heat loss to the surroundings. At the equilibrium temperature the sphere falls through the ring. (a) What is the thermal equilibrium temperature? (b) What was the amount of heat that was transferred between the ring and the sphere? (e) Which object lost the heat and which object gained the heat? (d) What is the mass of the aluminum sphere? Do not use the definition of density to solve for the mass.

The American Burn Association states 3. You heat up an aluminum sphere of radius r, 1.27254 cm to 100 °C. You cool a 20.0 g copper ring to 0.00000 °C. The inner radius of the copper ring is r, 1.27000 cm. You then place the sphere on top of the ring and they are allowed to reach thermal equilibrium. Assume no heat loss to the surroundings. At the equilibrium temperature the sphere falls through the ring. (a) What is the thermal equilibrium temperature? (b) What was the amount of heat that was transferred between the ring and the sphere? (e) Which object lost the heat and which object gained the heat? (d) What is the mass of the aluminum sphere? Do not use the definition of density to solve for the mass.

icon
Related questions
Question
The American Burn Association states 3. You heat up an aluminum sphere of radius r, 1.27254 cm to 100 °C. You cool a 20.0 g copper ring to 0.00000 °C. The inner radius of the copper ring is r, 1.27000 cm. You then place the sphere on top of the ring and they are allowed to reach thermal equilibrium. Assume no heat loss to the surroundings. At the equilibrium temperature the sphere falls through the ring. (a) What is the thermal equilibrium temperature? (b) What was the amount of heat that was transferred between the ring and the sphere? (e) Which object lost the heat and which object gained the heat? (d) What is the mass of the aluminum sphere? Do not use the definition of density to solve for the mass. O
Transcribed Image Text:The American Burn Association states 3. You heat up an aluminum sphere of radius r, 1.27254 cm to 100 °C. You cool a 20.0 g copper ring to 0.00000 °C. The inner radius of the copper ring is r, 1.27000 cm. You then place the sphere on top of the ring and they are allowed to reach thermal equilibrium. Assume no heat loss to the surroundings. At the equilibrium temperature the sphere falls through the ring. (a) What is the thermal equilibrium temperature? (b) What was the amount of heat that was transferred between the ring and the sphere? (e) Which object lost the heat and which object gained the heat? (d) What is the mass of the aluminum sphere? Do not use the definition of density to solve for the mass. O
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 7 steps with 7 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer