The average number of operational losses in a year at a particular plant is 18, so the number of losses in a year is distributed Poisson, with mean 18.) Given the distribution parameter from the previous question: What is the average number of weeks between operational losses (assume 52 weeks per year)? What is the probability that two operational losses will occur within two weeks of each other (i.e., given an operational loss today, what’s the probability the next one will happen in less than two weeks)?
The average number of operational losses in a year at a particular plant is 18, so the number of losses in a year is distributed Poisson, with mean 18.) Given the distribution parameter from the previous question: What is the average number of weeks between operational losses (assume 52 weeks per year)? What is the probability that two operational losses will occur within two weeks of each other (i.e., given an operational loss today, what’s the probability the next one will happen in less than two weeks)?
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter12: Queueing Models
Section12.5: Analytic Steady-state Queueing Models
Problem 13P
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- The average number of operational losses in a year at a particular plant is 18, so the number of losses in a year is distributed Poisson, with mean 18.) Given the distribution parameter from the previous question:
- What is the average number of weeks between operational losses (assume 52 weeks per year)?
- What is the probability that two operational losses will occur within two weeks of each other (i.e., given an operational loss today, what’s the probability the next one will happen in less than two weeks)?
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